No -- the two scope grounds (one under the other, but connected together) are connected at the same location as shown in the schematic, "north" of the 1 ohm CSR. The scope probes are then connected at points V1 and V2 shown in the schematic. The larger cables coming in from the right are from the power supply, connected also as shown in the schematic.
Because of the location of the scope grounds, if a battery were used, the CSR1 voltage and the power appear as negative, as expected from the schematic.
Okay , sorry this is confusing. So, as I understand: -The red and the black leads on the right of the picture are the power supply. -Both scope grounds are connected together . They are connected to CSR1 on the 'far' (away) side of the (-) of the power supply, labeled P11G and P12G in the schematic. P21G is also connected here. This ground is common across all calculated scope channels. -This leaves us with three remaining scope probes (V1, V2, and V3). And V4 which is the same as V2. -V1 (for measuring input power) is connected to the (+) of the power supply . [aka. P11T] -V2 (for measuring input power) is connected to the (-) of the power supply, on the power supply side of CSR1. [aka. P12T] -V3 (for measuring output power) is connected to the (+) of the LED, aka. the collector of the 2N2222 NPN transistor. [aka. P21T] -V4 (for measuring output power) is the same waveform as probe V2. Power_in = MEAN(V1*V2). Aka the total power of the battery and CSR1 together. Aka Pitotal. Power_out = MEAN(V3*V2) Aka the total power of the LED and transistor together. Aka Pototal. Is this correct? Does any one else have an opinion on these methods? Also PhysicsProf , did you get a chance to check the COP range of the 1K variable resistor which replaced the LED? Thanks -Feynman
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