I did many different designs on captrets until I got to this one. What bothers me is that battery voltage now is 1 full volt ABOVE resting initial voltage of the batteries. They are pretty much dead and they were sitting for days untouched on that resting voltage, also on my last video one can see that the LED is slightly brighter now not dimmer.
Fausto:
Which battery is going up in voltage, B1 or B2 or both? You should know this. It's a mistake on your part to not be recording the individual battery voltages separately.
Assuming that I am correct and B1 is being clamped to the forward voltage of the 5-watt LED, and that's about 7 volts, then as B1 starts it's very very long "dance of death" with the LED, the voltage across B1 should decrease very very slowly.
If this is true then you can assume that it's the voltage across B2 that is going up.
In my previous posting I stated that it looks like all of the action is across B1 and that B2 is doing nothing. There is an easy way to check this. You can swap out B2 for a 20,000 uF capacitor charged to 12 volts and run the circuit and see what happens. It looks to me like the voltage across the capacitor will slowly drift but I am not sure it it will drift up or down. Supposing that you do the test and find that the voltage across the capacitor drifts down by 0.5 volts in two minutes.
That would give you a pretty good idea about what was happening with B2. You know the size of the capacitor and the voltage change over two minutes. Therefore you know how much charge left the capacitor over the period of two minutes. That can then be converted to an average current flow measurement.
Now that you know the average current flow out of (or into) the capacitor, you now know what the average current flow out of (on into) the B2 battery is when it is plugged into the circuit. Therefore you know the average power flowing out of (or into) the B2 battery.
Assuming the current flow is very tiny then the power flow is also very tiny. If the B2 battery is relatively new and has a good charge, then the voltage drifting up is probably just a normal property of the battery. It doesn't make sense that a very tiny power flow out of (or into) the battery would cause a one volt increase in the battery voltage so the only rational explanation is that the battery voltage is just spontaneously changing. I honestly would find this strange though. A good battery with a good charge should not show a one volt change under these conditions.
On the other hand, if the B2 battery is old and weak, then it can be expected that it's voltage will fluctuate. If you made a separate measurement of the B2 battery's output impedance then you would have a good idea if it would be prone to a voltage fluctuation. As a reminder, if you measure a high output impedance, it could indicate that it's a perfectly good relatively new battery that is very close to being fully discharged. It's also possible that measuring a high output impedance means that the battery is old and weak and can't hold any charge any more. As you use your batteries and you get to 'know' them then you should be able to tell one from the other. I think in your clip that you state they are old old batteries from all of your Bedini motor testing so I would not be surprised if they are old worn out batteries with a higher output impedance even when fully charged.
The key point is that I am making the assumption that the B1 battery is fixed and clamped to about 7 volts because of the 5-watt LED. The B1 battery voltage should be rock solid, and only very very slowly decrease over time. The should be no fluctuations up and down on this battery's voltage.
MileHigh
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Topic: Captret (Read 26302 times)
