I disagree. The earth's field experiment is very much like the one I describe, you have the obsever rotating with the magnet. The non-uniformity of the B field would also apply to the Faraday disc experiment, the field is not uniform across the disc, but that does induce according to F=q.VxB even when the disc moves with the magnet.
Again I disagree, we don't consider those velocities in the Faraday disc experiments.
If you apply that argument to the Faraday experiment you are completely wrong. The earth's field experiment is just something larger than the Faraday one....
You disagree because you haven't interpreted my comments correctly.
The question of whether the magnet is rotating or not is irrelevant as long as the magnetic field remains the same, which is the case when a cylindrical magnet rotates around its magnetic axis.
The only question is: who is the observer who sees the charges at speed V?
Obviously it's the voltmeter connected to the sliding contacts that are at rest. It sees the electrons spinning and therefore sees the Lorentz force acting on them. If the voltmeter turns with them, it won't measure anything, which is what my experiment with the radial capacitor confirmed.
So in the case of the Faraday disc, obviously the speed of the earth plays no role, because the observer is on earth. But in the context of this thread, where the “observer”, the voltmeter, moves with the circuit, but is claimed to be measuring a current, then the speed of the whole through the galaxy should also have an effect. Obviously this is all wrong.
The voltmeter has speed zero in relation to the charges in the circuit, the Lorentz force is zero on all the charges it sees, so it cannot measure a current. The presence of the ferrite doesn't change anything because the Lorentz force is zero. Your remark ‘the conductors negates this cancellation’ is irrelevant, since there is no force on the electrons, so there is nothing to cancel, everything is already zero.
The Lorentz force on electrons in a circuit involving current can only be invoked when there is relative velocity between charges! In the end, these authors' paper makes no sense in terms of theory.
Secondly, when I spoke of a ‘uniform field’, I was simply referring to the experimental context of the experiment you proposed: when you rotate a magnet, it's almost impossible to avoid small variations in B, which could cause artefacts of a few µV in the measurements, whereas the Earth's magnetic field is considerably more uniform and stable. I wasn't referring to the cut-off flux.
If we talk about this, then it is clear that there is a variation in flux in the case of the Faraday disc. The flux through the disc is constant, but not through the circuit, because the rotation of the disc tends to change the circuit, and therefore the flux, by moving the charges participating in the current. In other words, in the case of the Faraday disc, Stokes' theorem is also valid. All this is known and calculated for a long time.
In the case of a rigid circuit moving with the earth, there is no variation in flux through the circuit. By Stokes' theorem, there is no current in the circuit either, which is perfectly in line with the absence of Lorentz force.
If there is a current, its cause really has nothing to do with the Lorentz force.
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Topic: Free electricity using Earth's rotational energy? (Read 5519 times)
