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Author Topic: Free electricity using Earth's rotational energy?  (Read 3697 times)
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Here is a FEMM run of a Ferrite tube in a uniform magnetic field.  Shown there are two conductors crossing that field, one inside the tube and one outside the tube.  I show the B field magnitudes given by FEMM for the two positions.  The field inside the tube is virtually zero.  Now if the tube and the conductors move together in the x direction will there be a difference in the v X B electric field seen by the conductors?  If the zero B field at the inner conductor results in zero v X B electric field on that inner conductor then the answer is a resounding yes. 
<Snip>
Smudge

Hi Smudge,
Interesting. I appreciate the FEMM. And agree for a static condition. However when there is motion, left to right, on the diagram, field lines move from one side of the tube to the other. Since, as we are taught, these lines are continuous and remain unbroken, they must cross the conductor which is inside the tube. This infers that both conductors will have equal lines "cut" for a distance traveled in a uniform field, would it not?
bi
   

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Hi Smudge,
Interesting. I appreciate the FEMM. And agree for a static condition. However when there is motion, left to right, on the diagram, field lines move from one side of the tube to the other. Since, as we are taught, these lines are continuous and remain unbroken, they must cross the conductor which is inside the tube. This infers that both conductors will have equal lines "cut" for a distance traveled in a uniform field, would it not?
bi
Yes you can consider lines entering the moving tube on one side and leaving on the other side, but no lines appear inside the tube where the field remains at zero.  FEMM has the capability of giving you the vector potential A field that lies along the z dimension parallel to the conductors.  When you examine that and use E=-dA/dt instead of flux cutting E=vXB you find that both conductors endure the same E field so the closed loop induction is zero.  My take is that the flux cutting rule cannot be used under all situations but E=-vXB is more fundametal and can be used.

The first image below shows a red line where FEMM has given a chart of the A field along the line.  The second image shows two charts superimposed for the initial case and for a 10mm movement of the tube and conductors.  It is seen that both conductors obtain the same change of A field.

Smudge
   

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If our wire put inside a tube from superconductor instead ferrite? There will be not magnetic field there  at all.   ;) in deed.
   
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Yes you can consider lines entering the moving tube on one side and leaving on the other side, but no lines appear inside the tube where the field remains at zero.  FEMM has the capability of giving you the vector potential A field that lies along the z dimension parallel to the conductors.  When you examine that and use E=-dA/dt instead of flux cutting E=vXB you find that both conductors endure the same E field so the closed loop induction is zero.  My take is that the flux cutting rule cannot be used under all situations but E=-vXB is more fundametal and can be used.

The first image below shows a red line where FEMM has given a chart of the A field along the line.  The second image shows two charts superimposed for the initial case and for a 10mm movement of the tube and conductors.  It is seen that both conductors obtain the same change of A field.

Smudge

Thanks Smudge,
My take is that the moving tube cuts lines, so that which is inside the tube cuts lines. It seems to work in this case even though FEMM never shows flux inside the tube. I do appreciate your explanation.

Flux cutting is E=-vXB. E=-dA/dt is the more fundamental, right?
bi
« Last Edit: 2025-04-12, 18:39:07 by bistander »
   
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But since Stokes’ is just vector math, and our concept of vector fields is a simplification of the real situation of trillions of atomic orbiting electrons in one region of space influencing trillions of conduction electrons in another region of space, is it not possible that Stokes’ would not apply in certain cases?

A vector field is first and foremost a model. In the case of the magnetic field, the B field allows us to characterise space locally rather than using the billions of billions of equations describing each interaction at a distance with a delay, of each charge with each other.

If anyone has a better model, don't hesitate to provide it.

You can always imagine that since it's a model, and since it would be a simplification, phenomena could deviate from it. Even if we don't assert that something is true because it hasn't been shown to be false, we assume it, which is simply the argument from ignorance, and therefore an irrelevant argument.

Even if the experiment we're talking about produces a current, we don't even need to assume that the field model or Stockes' theorem wouldn't apply, as long as we don't have experimental confirmation that not only is there a real current produced but that no field model would explain it, for example by adding the field of a source we hadn't thought of.
On the other hand, since no experiment has yet shown a deviation from field theory, we can say that it is highly improbable that this would be the case here, and that it is up to those who are convinced of the contrary to demonstrate it.

...When you examine that and use E=-dA/dt instead of flux cutting E=vXB you find that both conductors endure the same E field so the closed loop induction is zero.  My take is that the flux cutting rule cannot be used under all situations but E=-vXB is more fundametal and can be used.
...

The flux cutting rule is generally false, except when applied in the near-field approximation, i.e. when field propagation times can be neglected. Here, it is correct.  Sometimes it's also difficult to identify, as in the case of the Faraday disk.

As for using A instead of B, we've already done quite a bit of work on this, remember, and it turns out that the electromagnetic results agree, since what links them is not a physical theory but a purely logical mathematical relationship.
The only problem we have is when we limit ourselves to 3D Euclidean space when we live in a 4D universe.
We even see, which surprised me at first, that a scalar potential φ can appear in the charge referential when it moves in a place where there is only the vector potential. And vice versa”.
https://www.overunityresearch.com/index.php?topic=4389.msg103488#msg103488

When we use the 4-vector, many surprises disappear!



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Buy me some coffee


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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That said, experiments takes precedence over theory. So if the current they're measuring isn't just an artefact, even if their theory is bogus, that doesn't mean their setup isn't worth exploring.
I agree as it could show something that has been missed in our theories.  An experiment conducted at the equator would involve using a vertical assembly, but why not do the equivalent at a much higher rotational speed using a laboratory magnet?  The composite image below shows first a variation of the Faraday homopolar generator where the disc is moved from the pole to the equator.  The magnet plus disc (annulus) is rotated.  The magnet is a conducting one and we would expect to get a measurable voltage across the brushes. In the second image the meter rotates with the magnet and we would expect a zero voltage.  The third image includes the ferrite tube, and if this shows a voltage then we need to find out why.

Smudge
« Last Edit: 2025-04-18, 16:20:38 by Smudge »
   
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@Smudge

What I can say is that in the middle image, we don't have zero. There is a current if one of the contact points is towards the middle of the cylinder (from which no field line emerges), and the other towards one end, i.e. there is a field gradient between the two.
This is what I had demonstrated experimentally, and which we had already discussed here: https://www.overunityresearch.com/index.php?topic=3738


The only difference was that the rotating shaft was not a magnet, but ferromagnetic and magnetized at a distance by a magnet.

Your case 3 with ferrite should therefore also show an EMF.


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@Smudge

What I can say is that in the middle image, we don't have zero. There is a current if one of the contact points is towards the middle of the cylinder (from which no field line emerges), and the other towards one end, i.e. there is a field gradient between the two.
This is what I had demonstrated experimentally, and which we had already discussed here: https://www.overunityresearch.com/index.php?topic=3738


The only difference was that the rotating shaft was not a magnet, but ferromagnetic and magnetized at a distance by a magnet.

Your case 3 with ferrite should therefore also show an EMF.

Sorry I did not make it clear that in the bottom two images the meter is connected to the magnet and revolves with it.  I have edited the images to make them more like the experiment under discussion.

Smudge
   
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@Smudge

Sorry, I misinterpreted your diagrams. But I don't see what the ferrite is for. An electric field from a dB/dt cannot be masked. On the other hand, as the whole device is rigid and rotates in a constant field, it is invariant to rotation, so no force is to be expected on the electrons.

A few days ago I came across a revolutionary theory of electromagnetism, treating charges in the same way as masses through relativity, based on Weyl geometry : https://iopscience.iop.org/article/10.1088/1742-6596/2987/1/012001 .
Electrons thus follow geodesics according to the principle of least action. In this theory, the Lorentz force becomes a fictitious force, an idea you had imagined in the Coler/Unruh thread. This theory may therefore be of interest to you, especially as it also reactivates the idea of the ether, which the quantum vacuum actually becomes and whose charge is a compression. It explains the Aharonov-Bohm effect.

I haven't yet had time to look at it all in detail. Unfortunately, this theory is difficult and requires a level of mathematics that I don't have. But it seems simple and elegant on the principles, electromagnetism becomes a geometrical theory like relativity. It would be interesting to try to use it qualitatively on our problems (quantitatively seems out of reach to me).

A few extracts:  "The Lorentz force law is derived from the same metrics as a geodesic equation. The charge density is shown to obey a covariant wave equation, which indicates that charge density is a field, which propagates at the speed of light. This viewpoint promotes the wave-picture of the electron."
"As the electrodynamic force, i.e. the Lorentz force can be related directly to the metrical structure of spacetime, it directly leads to the explanation of the Zitterbewegung phenomenon and quantum mechanical waves as well."
"Charge is therefore to be understood as a local compression of the metric in the spacetime, which relates to longitudinal waves as described in [12]."


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@Smudge

Sorry, I misinterpreted your diagrams. But I don't see what the ferrite is for. An electric field from a dB/dt cannot be masked. On the other hand, as the whole device is rigid and rotates in a constant field, it is invariant to rotation, so no force is to be expected on the electrons.

This is simply the earth's field experiment discussed here that gave 18uV reading, replicated using a magnet in place of the earth.  We get greater field and greater rotation speed, but it's the same experiment.  Big disadvantage is the meter revolving with the magnet is somewhat difficult to read.  A variation where the meter is stationary is shown in the images below.  This uses plastic annuli attached to the magnet carrying a radial conductor.  We know we will get a voltage from image 1 and zero from image 2, but what will we get from image 3?  You will say zero but the earth's field experiment did not yield zero.  It strikes me that this experiment where we can vary the rotation speed is more likely to find answers than another earth's field one.

Quote
A few days ago I came across a revolutionary theory of electromagnetism, treating charges in the same way as masses through relativity, based on Weyl geometry : https://iopscience.iop.org/article/10.1088/1742-6596/2987/1/012001 .
Electrons thus follow geodesics according to the principle of least action. In this theory, the Lorentz force becomes a fictitious force, an idea you had imagined in the Coler/Unruh thread. This theory may therefore be of interest to you, especially as it also reactivates the idea of the ether, which the quantum vacuum actually becomes and whose charge is a compression. It explains the Aharonov-Bohm effect.

I haven't yet had time to look at it all in detail. Unfortunately, this theory is difficult and requires a level of mathematics that I don't have. But it seems simple and elegant on the principles, electromagnetism becomes a geometrical theory like relativity. It would be interesting to try to use it qualitatively on our problems (quantitatively seems out of reach to me).

A few extracts:  "The Lorentz force law is derived from the same metrics as a geodesic equation. The charge density is shown to obey a covariant wave equation, which indicates that charge density is a field, which propagates at the speed of light. This viewpoint promotes the wave-picture of the electron."
"As the electrodynamic force, i.e. the Lorentz force can be related directly to the metrical structure of spacetime, it directly leads to the explanation of the Zitterbewegung phenomenon and quantum mechanical waves as well."
"Charge is therefore to be understood as a local compression of the metric in the spacetime, which relates to longitudinal waves as described in [12]."
Thank you for that, I will study it with interest.

Smudge
   
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...
Big disadvantage is the meter revolving with the magnet is somewhat difficult to read.  A variation where the meter is stationary is shown in the images below.  This uses plastic annuli attached to the magnet carrying a radial conductor.  We know we will get a voltage from image 1 and zero from image 2, but what will we get from image 3?
...

There's a simple way to carry out the experiment: replace the voltmeter by a capacitor, rigidly connected on one side, and with a light contact on the other, with a sort of ratchet. The speed of rotation is slowly increased, and once a certain threshold is reached, the centrifugal force on the capacitor causes it to disconnect. We can then stop the rotation and quietly measure the voltage across the capacitor.
I did this experiment in the context of the Faraday disk, with a capacitor placed radially and rotating with the disk, in order to verify the absence of voltage in the rotating frame of reference, which the experiment did indeed show.

In the present case, I'm not inclined to do so. For one thing, the experiment is very different from that of the terrestrial field, because the B field cannot be uniform throughout space. On the other hand, if the theory were true, i.e. that speed would have an influence, we'd have measurements that would also depend on the speed of the earth around the sun, or the speed of rotation of our galaxy, which are much greater than the linear speed at the earth's surface due to its angular velocity.

In F=q.VxB, V is the velocity of the charge relative to the observer who sees B, not relative to the source of the field. The observer at the earth's surface will see F=0 because V=0, ferrite or not.

If the effect is real, it can't be a question of the conductor's speed, but perhaps of acceleration. We have two of these: gravity acceleration and centrifugal acceleration. It's possible that the positioning of the device in relation to the accelerations and the B field, and its nature thanks to the ferrite, could produce an imbalance somewhere on a closed circuit, resulting in a non-zero net force on the electrons, knowing that the energy could only be taken from centrifugal acceleration, slowing down the earth. I think that's where we should be looking.



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....the experiment is very different from that of the terrestrial field, because the B field cannot be uniform throughout space.
I disagree.  The earth's field experiment is very much like the one I describe, you have the obsever rotating with the magnet.  The non-uniformity of the B field would also apply to the Faraday disc experiment, the field is not uniform across the disc, but that does induce according to F=q.VxB even when the disc moves with the magnet.

Quote
On the other hand, if the theory were true, i.e. that speed would have an influence, we'd have measurements that would also depend on the speed of the earth around the sun, or the speed of rotation of our galaxy, which are much greater than the linear speed at the earth's surface due to its angular velocity.
Again I disagree, we don't consider those velocities in the Faraday disc experiments.

Quote
In F=q.VxB, V is the velocity of the charge relative to the observer who sees B, not relative to the source of the field. The observer at the earth's surface will see F=0 because V=0, ferrite or not.

If you apply that argument to the Faraday experiment you are completely wrong.  The earth's field experiment is just something larger than the Faraday one.  By your reasoning, if we had a giant disc at the pole and an observer who was not rotating with the earth (but was translating with the earth around the sun etc.) had a voltmeter connected to brushes on that disc would not measure anything.  I think he would as it is just a giant Faraday disc experiment.

I stand by my perception that a radial conductor at the equator is just a larger version of the radial conductor in my experiment and it will inherit an induced E field.  The reason the closed circuit sees zero voltage is the two radial conductor's voltages cancel out.  The non-zero result of the actual earth's field experiment suggests that having ferrite around one of the conductors negates this cancellation.  Surely this is something worth investigation to see if it is true.

Quote
If the effect is real, it can't be a question of the conductor's speed, but perhaps of acceleration. We have two of these: gravity acceleration and centrifugal acceleration. It's possible that the positioning of the device in relation to the accelerations and the B field, and its nature thanks to the ferrite, could produce an imbalance somewhere on a closed circuit, resulting in a non-zero net force on the electrons, knowing that the energy could only be taken from centrifugal acceleration, slowing down the earth. I think that's where we should be looking.
OK but I think that is far more speculative than my approach.  In my simple mind if a conductor is within a magnetic field that is a constant value and somehow Nature has has arranged that its movement through that field can induce a voltage, then perhaps Nature also has a way of doing something to some magnetic material that is moving, something we don't know yet.

Smudge
   

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Maybe we should change the planet so that there is enough energy for everyone?
   
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