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2025-04-01, 02:01:07
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Author Topic: Checking out Joel Lagace - Hang on I'M SERIOUS!!  (Read 14572 times)

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Dear Howerd,

IMHO the energy by which your neon bulbs are lit for a certain time does not come from the enviroment, it came first from the two 1.2 V batteries, then the received HV influenced the dielectric material in the capacitors and after switching off the batteries, the dielectric material released the received energy.
An electret does get energy (it should get) from a high voltage source that must be furnished in for influencing the dielectric material and the latter then can release it till most the charge particles etc reoccupy their original position in the dielectric material.   Then the electret is depleted  like your capacitors in the box.

I agree that Joel could join in here and a civilized conversation could start. However, as I understood him from the videos, he has commited himself to a kind of company forming etc so if this materializes, then he will not share crucial details.  If there is indeed real COP values he claims being much higher than 1.

Gyula
If that is the case then Joel's experiment can not work as I think.
How do you think it works?


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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If it really is "a much more efficient way to get to the required result" i have my doubts as it is not based on any logic IMO.

Itsu

It is based on the way a capacitor works over time. The first few percent charge up almost instantly, and then the ability to accept electricity starts to slow. If we have 4 caps in series, we get to the required voltage a lot quicker.
Getting to the required voltage quicker = much more efficiency.
Also  much more dielectric absorption (4 caps instead of 1)
Also, the electret effect as Gyula describes.
I also appreciate that the Farads divide by 4 and this is a mistake in Lagace's video.
However, our C.O.P. calculations took his mistake into account and the C.O.P. was still in the hundreds.
In other words, we based our calculations on cap 3 = 2.5 kFarads
The cop calculations did not take the cost of pulsing via the FG system into account

It remains to be seen if Gyula  is correct that all the energy comes fom the battery in the first place or if there is something else at play


---------------------------
Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   
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If that is the case then Joel's experiment can not work as I think.
How do you think it works?

The question is what we mean on "it works"?   COP less than 1 or COP higher than 1?

Joel did not show in (his latest) video details which would be needed to know for correctly judging his setup's exact operation.  Itsu included all the data needed for evaluating his setup and he got COP less than 1.

IF Joel's supercaps has been 'conditioned' by HV before (no info was given on this in the video) he made the video then it is different story and we do not know for instance how long it could have run with the claimed COP>1, etc.

Gyula
   

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watching Akings vid, was wondering if the caps heat up a bit and expand a bit.  could it be cooling and contracting, therefore the rundown spark?  would be interesting once the sparking discontinued if we were to cool it down further if it would spark some more, or if it were heated up if the sparking would stop..  just thining

mags
   

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watching Akings vid, was wondering if the caps heat up a bit and expand a bit.  could it be cooling and contracting, therefore the rundown spark?  would be interesting once the sparking discontinued if we were to cool it down further if it would spark some more, or if it were heated up if the sparking would stop..  just thining

mags
It would be nice if you could replicate the effect.
I realized a long time ago that two heads are better than one.
I first discovered the effect using 4.7uf 400v caps from cannibalized dead CFLs.  There are loads of useful components
inside those things: A nice choke, a simple trafo, a bridge rectifier, and a very nice electrolytic 4.7 uf 400v cap and other small caps.
Also, they are designed to work at about 27 KHZ - ie HF components.


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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so those caps in the vid are 4.7uf

mags
   

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so digging through circuit boards, ive found 4 sets of 3 same value, same brand caps.
100uf 100v
470uf 100v
1000uf 50v
4700uf 16v

also found some T0220 dual diodes that are .222 drop. will get a spec sheet

first will try the caps to try to get most of cap A to cap B via the toroid winding and the diode, trying different voltages for each to get the best match before core saturation.

mags
   
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so those caps in the vid are 4.7uf

mags

Hi Mags,

Which video you mean?  This one by Aking?  https://www.youtube.com/watch?v=fBR2tOTsyfg   If yes, then back then when the video was made the capacitors were 1 uF, 600V rated, Grumage confirmed that back then (in 2023). This is why I based some calculations above in my post on that.

Maybe Aking wishes to chime in with any correction if needed. Probably his capacitors back then were not electrolytic types.

Gyula
   

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As suggested by Aking.21, i changed C3 to be 4x 100F in series, meaning 25F using the last setup (CMC 1:1 transformer, schottky diode bridge).

The circuit now looks like this:



Again i shorted C2 and C3 to be 0V, and charged C1 to 2.7V.

I did not record all the data, i initially wanted to just note down the start and end voltages, but as C3 started rather quickly to load up and even increased more than C1 i noted down the data after 1 hour which was:

                C1                         C2                           C3
Start         2.7V    (364.5 J)     0V       (0 J)             0V        (0 J)
1 Hour      1.852V (171.5 J)    1.028V (52.84 J)       1.927V (46.42 J)
running....


So it seems that having for C3 4x caps in series OR having a lower value cap for C3 (or both as in this case) we see C3 voltage increase quickly and even increase more than C1.
It however does not seem to contain more energy together with C2 then C1 has, but it might LOOK like we have more energy in C3 then in C1, thus LOOKS like overunity.

So are the caps in Joel his video really 4x 10000F (2500F) or less?

I will keep it running overnight to see what the end result will be, but as it changes very slowly now i do not expect a large change....

Itsu
   

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Hi Mags,

Which video you mean?  This one by Aking?  https://www.youtube.com/watch?v=fBR2tOTsyfg   If yes, then back then when the video was made the capacitors were 1 uF, 600V rated, Grumage confirmed that back then (in 2023). This is why I based some calculations above in my post on that.

Maybe Aking wishes to chime in with any correction if needed. Probably his capacitors back then were not electrolytic types.

Gyula

1uf.  hmmm.  i was thinking 4.7uf as Aking seems to have sugested in the previos post might be qite small to afford that much self sparking after the hv power input was disconnected.  each spark should have drained those small caps very quickly.  that was why i questioned about if the hv leads from the transformer were also disconnected also, to eliminate the posisbility of rundown with that after power input was removed as seen in the vid.  if they are 1uf, then i would suspect that even more.

mags
   

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so those caps in the vid are 4.7uf

mags
No, I was talking about the first time I got the effect.
I have measured the current caps as in the video:
They are highly unstable with varying capacities.
After some settling down I got:  each cap 500 pf @100 Hz ; 470 pf @10KHZ
I ony measured the 1st cap in the series (disconnected).
5 caps in series: 402 pf sometimes 325 pf at 100 Hz.

So the mathematics doesn't add up. (Not my fault).
The meter used was DER EE DE-5000
Grumage has the same caps, (he sent them to me) maybe he has some more info.

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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The overnight run was not conclusive as the 9V battery powering the little FG got drained and the FG stopped working at some time, but the results after 13 Hours on the meters were:

                  C1                           C2                             C3
13 hours     1.651V (136.3 J)       1.092V (59.62 J)        2,2V  (60.5 J)   


Doing the calculations anyway: we started with 364.5 Joule in C1
C1 ended with 136.3 Joule left over
C2 ended with 59.62 Joule left over
C3 ended with 60.5 Joule left over.

So overall we started with 364.5 J and ended with 256.42 Joule, so no gain noted here.


If we only take the data from after 1 hour running, we get:

Starting with 364.5 J, ending with 171.5 + 52.84 + 46.42 = 270.76 Joule, so also here no gain noted.

I will do another run making sure the FG keeps on running.

Itsu
   

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The overnight run was not conclusive as the 9V battery powering the little FG got drained and the FG stopped working at some time, but the results after 13 Hours on the meters were:

                  C1                           C2                             C3
13 hours     1.651V (136.3 J)       1.092V (59.62 J)        2,2V  (60.5 J)   


Doing the calculations anyway: we started with 364.5 Joule in C1
C1 ended with 136.3 Joule left over
C2 ended with 59.62 Joule left over
C3 ended with 60.5 Joule left over.

So overall we started with 364.5 J and ended with 256.42 Joule, so no gain noted here.


If we only take the data from after 1 hour running, we get:

Starting with 364.5 J, ending with 171.5 + 52.84 + 46.42 = 270.76 Joule, so also here no gain noted.

I will do another run making sure the FG keeps on running.

Itsu
I notice your circuit seems more efficient after 1 hour of running than at the end. Is that because the FG stopped running you think?


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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I don't think so, it probably is due to the nature of the (dis)charge speed which is fastest at the start, then slowing down gradually because of the internal resistances staying constant while voltage is decreasing, thus getting this funnel shape graph i showed in my earlier posts.

Itsu
   

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I restarted the last setup again this morning and after 24 hours running we got this data:

                   C1                          C2                          C3
start            2.7V                       0V                           0V
6 hours      1.704V                     1.156V                     2.08V
11 hours    1.618V                     1.194V                     2.13V
24 hours    1.455V (105.85 J)     1.255V  (78.75 J)      2.18V  (59.4 J)
33 hours    1.349V (90.99 J)      1.29V   (83.2 J)         2.2V   (60.05 J)
48 hours    1.249V (78 J)           1.311V  (85.94 J)      2.22V  (61.6 J)

 i will keep it running some days.

Itsu
« Last Edit: 2025-02-26, 09:12:38 by Itsu »
   

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one of the issues with cap to cap as you see here is that capA at 2.7v, has the highest pressure, potential, at first but deteriorates double time as cap B takes on potential. the first pulse is the most powerful. as it goes along, the voltage across the primary can only be the difference in voltage cap A minus cap B. 

eventually we should end with 1.35v in each cap A and B in an ideal situation.  each holding only 25% of the original cap A energy.
so, im wondering how much could go to cap C if we just used cap A, nix cap B and just charge cap C.  im thinking the outcome can be a better eff than what we are seeing cap to cap charging cap C


on my end, the list of caps i posted are too much for the inductance of the toroid winding.  1.6mh.  the max flux happens too quickly thus max current.  like the 1000uf almost acted like simple cap to cap with just a variance in voltage diff.  100uf showed inprovement.  say 20v ended 6v cap A and 14v cap B.  little lower due to diode.  so i finally went to 2uf plastic dip 100v.  works as intended but the caps leak down quickly.  so possibly go to electrolytic will help with that.  also need to try 10uf, some below 100uf.  testing....

even though i was down on the cap to cap above, my approach is dealing just 1 shot cap A to cap B being the toroid winding is very close to lenzless and hope for output on cap C.

i have another orbo wound with more turns of finer wire.  need to find that, or rewind a new one with a higher inductance.


mags
   

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I have updated my previous post with 24H data.

So we now (24H) have:

C1 = 105.85 J
C2 plus C3 = 138.15

There seems to be more energy in C2 and C3 together as there is now energy left in C1

Total energy started with was 364.5 J in C1, and left over in all 3 Caps now is 244 J so still overall we loose (but we always do if paralleling caps).

At the end we suppose to have an equal amount of energy left in C1 and C2 ( without C3 1.35V = 182.25 / cap) but that we are not going to get anymore due to the transfer to C3.

I will keep it running for some time to see if we get an equal amount of energy in C1 and C2.

Itsu
   

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Mags, I see you are trolling F6FLT  - good on you. You've plenty of available science to prove him wrong.

You once asked me about my little device.
Well, here it is: Consistently showing zero amps and zero volts yet charging a very big 12 volt battery.
It is a simplified diagram of Lagace's free energy from the energy company (which is not the case).
How it works:
1. A mains rated less than 1uf capacitor is charged by the mains in the first half cycle.
2. The capacitor discharges this power back into the mains in the next half cycle. This process repeats at 50 or 60 cycles per second.
3 The sequence is interrupted by a bridge rectifier that charges your 12-volt battery.
It is called reactive power, but it is essentially your own power which you have paid for bouncing back and forth between
the electricity company and your capacitor minus system losses.
4 The additional power can only come from the electrostatic field in my opinion or the power meter is wrong.

I estimate that about 2 watts of energy is being created.
The choice of capacitor matters very much. A bigger than 1uf cap and it immediately registers 1.2 watts and more.
I assume this is because the bigger cap puts higher resistance in the system.
If I introduce a spark gap into the circuit, resistance is immediately created and power is consumed and registered.
It is a delicate balance.  Introducing a trafo can also register sometimes. Sometimes not.
The first pic shows the system with the circuit encapsulated.
The second pic shows the actual circuit.
The third pic shows a transparent encapsulated circuit.
Either way, it is a highly efficient battery charger, and those with solar power and battery backup may be interested.



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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

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Meanwhile, i was revisiting the video at the first post of this thread and noted the following:

Joel says at:

1:03  "i charge Cap A (our cap C1) to 1.96V and discharged the other cap (pointing to our cap C2).
1:29  "switching in Hz which is the optimum" pointing to the FG which clearly shows to be set to 26.2 kHz. (so is it really the optimum then?)
1:55  "After 1 hour (after start i guess) we have 0.1V drop on Cap A (our cap C1) and a same 0.1V (-10%) increase on the other cap (our cap C2).
2:28  pointing to our cap C3 "this is a set of 10000F" which is hard to believe as the 4 caps are in series meaning 40000F each.
2:36  pointing to our cap C3 "set to zero" meaning at the start it was discharged to 0V IMO.
7:13  "it ran all night" showing the voltage across cap A (our cap C1) being 1.78V which means coming from 1.96V at start, a drop of 180mV   
7:55  we can see written on the top of one of the 4 series caps "10000", see attached picture.  So not 10000F, so still very doubtful these are real 10000F caps (4 in series mean 2500F).

In the comments below this video, there are also doubts about the value of the used C3 caps, but questions asked Joel are ignored (which i often see in his other video's where these 4 series caps are used.
He uses these 4 series caps already in this video:  https://youtu.be/Xr9QSD889ZA from 2 years ago, in which also the now used transformer is shown (Prim. 120VAC 60Hz 15W - Sec. 2.3V 3A).

From the above, we learn the values on his caps to be:

C1 charged to 1.96V (500F = 960.4J).
C2 and C3 drained to 0V
He says cap A (C1) dropped 100mV in the first hour and C2 (his other 500F cap) gained 100mV (meaning it was charged to 0.1V) and that this was going on in this relation.

He also says that at the time of the video the device was running all night and showed that C1 (his cap A) now measured 1.78V, so a drop from 1.96 of 180mV.
This thus mean, seeing the above statement, that C2 now should have gained 180mV so it should now measure 0.180V.

C1 started with 1.96V = 960.4J and ended with 1.78V = 792.1J so lost 168.3J
C2 started with 0V and ended with 0.180V = 8.1J  (which is hard to believe IMO, but as it was never measured or mentioned it could be anything).
C3 started with 0V and ended with 2.51V which for a 2500F cap mean 7875J (which is also hard to believe).

If we follow the suggestion of one of the responders under Joel his video that the 4 series caps more look like 100F caps (meaning a total of 25F) and we take the shown 2.51V then we have an energy of 78.75J in these caps which is much more believable and matches more the results i have.

I guess we will never know, as Joel ignorers questions about his 4 series caps value up till now.


Itsu
   

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C3 started with 0V and ended with 2.51V which for a 2500F cap ...
They make 2500 Farad capacitors now ?  :o
   

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I think this is a slightly clearer picture of the caps.


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Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   
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They make 2500 Farad capacitors now ?  :o

I think Itsu meant the 4 capacitors (10000 F each) connected in series resulted in 2500 F. 
   
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Hi Howerd,

If your capacitor is say 870 nF, then its capacitive reactance is around 3.65 kOhm at 50 Hz mains frequency,
This sets the battery charge current to around 65.5 mA AC with the 240 V mains.

Using say 1 uF capacitor, the reactance reduces to 3.18 kOhm and the charge current increases to 75.4 mA AC.
At the DC output of the diode bridge the charge current feeding the battery could be checked by a DC ampermeter, it should be in the above calculated range,
capacitor depending.

Your power meter is not wrong IMHO, it just has a limited lower measurement range, not specified below the 1 W or so consumed power. Maybe there is specification in
the user manual? What is the type of the meter? 

In your point 4 you wrote "The additional power can only come from the electrostatic field in my opinion or the power meter is wrong

Would like to ask where is this electrostatic field created you refer to?

Gyula



Mags, I see you are trolling F6FLT  - good on you. You've plenty of available science to prove him wrong.

You once asked me about my little device.
Well, here it is: Consistently showing zero amps and zero volts yet charging a very big 12 volt battery.
It is a simplified diagram of Lagace's free energy from the energy company (which is not the case).
How it works:
1. A mains rated less than 1uf capacitor is charged by the mains in the first half cycle.
2. The capacitor discharges this power back into the mains in the next half cycle. This process repeats at 50 or 60 cycles per second.
3 The sequence is interrupted by a bridge rectifier that charges your 12-volt battery.
It is called reactive power, but it is essentially your own power which you have paid for bouncing back and forth between
the electricity company and your capacitor minus system losses.
4 The additional power can only come from the electrostatic field in my opinion or the power meter is wrong.

I estimate that about 2 watts of energy is being created.
The choice of capacitor matters very much. A bigger than 1uf cap and it immediately registers 1.2 watts and more.
I assume this is because the bigger cap puts higher resistance in the system.
If I introduce a spark gap into the circuit, resistance is immediately created and power is consumed and registered.
It is a delicate balance.  Introducing a trafo can also register sometimes. Sometimes not.
The first pic shows the system with the circuit encapsulated.
The second pic shows the actual circuit.
The third pic shows a transparent encapsulated circuit.
Either way, it is a highly efficient battery charger, and those with solar power and battery backup may be interested.
   

Sr. Member
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Posts: 489


Buy me some coffee
Hi Gyula,

When you repeatedly charge and discharge a capacitor you are constantly charging and discharging an electrostatic field.
The air contains electrostatic energy as do various objects.
according to Chatgpt:
"A capacitor stores energy in the form of an electric field between its plates. Here’s how it works:
Charging the Capacitor: When a voltage is applied across the capacitor’s plates, electrons accumulate on one plate (making it negatively charged), while the other plate loses electrons (becoming positively charged). This creates a potential difference (voltage) between the plates.
Electric Field Formation: The separation of charges generates an electric field in the dielectric material (the insulating material between the plates). This field represents stored electrostatic energy."

If we want COP>1 we have to figure out how to use this available energy.
If we do nothing, our chance of success is zero.
If we work at it our chances of success may be minuscule, but they are not zero
Keep experimenting.


---------------------------
Electrostatic induction: Put a 1KV charge on 1 plate of a capacitor. What does the environment do to the 2nd  plate?
   

Group: Professor
Hero Member
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Posts: 3670
I think Itsu meant the 4 capacitors (10000 F each) connected in series resulted in 2500 F.
They make 10000 Farad capacitors now ?  :o
   
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