Hi Max,
why do you think that "Amplification" and "Resonance" are linked together?
When you look at this wiki: https://en.wikipedia.org/wiki/Resonance about resonance there you will not find any reference to amplification.
In the "Overview" part it nicely mentions that there are "some losses from cycle to cycle, called damping", so instead of amplification, there is always some dampening.
In the "Q factor" part it also mentions that: "A high value for Q indicates a lower rate of energy loss relative to the stored energy, i.e., the system is lightly damped".
Itsu
Excellent post, Itsu. Resonance directly will never produce OU, but you can use LCR circuits to produce effects that can AID in possible OU. If you have a simple boost circuit of a charge choke, mosfet, diode, and capacitor, as long as you have a constant DC input you will have a constant DC output. Now where does resonance come into this? If you remove the diode and replace it with a coil you will have a resonant circuit, the output will be a sine wave at the LC resonance. But there is still no OU!! So we make the resonant circuit into a resonating vibrator (loads and loads of delays). So we now have loads and loads of sine waves. But there still is no OU. All these waves have a high amplitude, they are all resonant, and because the mosfet switch is driven by a square wave, the LC frequency of the waves will be increased by the multiplication of the drive frequency of the mosfet. But still no OU. Now all these waves are sine waves, so we can place a diode on the output and collect the pulses in a capacitor. But this is still not OU. The voltage you have collected in the capacitor is HV, and if you could discharge it rapidly you would have a high current. But still not OU. I'm sure you are getting the idea. Regards Mike
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Topic: Akula, Ruslan, Stalker, device discussion and replications. (Read 54715 times)
