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Author Topic: William ENKI  (Read 9070 times)
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Hi Folks,

Regarding input and output measurements, member ION (unfortunately deceased 3 years ago) suggested looping circuit solutions to rule out errors.  You may find useful tips from him to apply to your circuits.

https://www.overunityresearch.com/index.php?topic=604.0   

https://www.overunityresearch.com/index.php?topic=452.0

Gyula
   
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I think the hardest part is measuring the input and output, especially measuring input power when there are extremely short spikes in power when charging capacitors. Most meters won't react quick enough to measure them, so you might be misled when it shows, say, 25W input power, when it might have spiked to 500W for less than a millisecond.

Hi Lee, 

Would like to mention, that normally the extremely short spikes riding on supply rails in such pulsed circuits carry but a negligible power just because of the very short time they exist.  A spike with a 500 W peak power may have say just under a watt average or mean power.   You could say "many a little makes a mickle" though...  C.C

...
Quote
I think what it boils down to is - charge a small capacitor to a high voltage using a fairly large resistance to limit current, then use this to charge a larger capacitor to a lower voltage via a coil / inductor (doesn't have to be an air core transformer like Don Smith did). I don't think it requires much current at all to charge a small capacitance. Don Smith used the fact that the secondary coil of a NST is current limited using a magnetic shunt (gap in core), which enables him to generate a high voltage at low current.

There is another way that I know of that works entirely from capacitors without involving a NST or ZVS. You pump power into a coil, turn it off sharply and then capture the inductive kickback to charge multiple capacitors via diodes. This is the method that John Bedini used. What he found was that you can charge multiple capacitors from the inductive kickback in parallel, where the coil becomes a current source at the point when the power is switched off abruptly. The quicker you turn off power, the quicker the magnetic field collapses, and the larger the kickback voltage will be. The magnetic field collapses at the speed of light, and this cuts through the wires and generates an EMF. The current continues in the same direction except that it is now reverse polarity compared to the original input current. John Bedini uses specially modified transistors to achieve a sharper turn off time. He cut off the tops of TO-3 transistors and connected a 'cat's whisker' wire to the silicon. These days we have super fast SiC MOSFETs capable of switching 2000V with rise & fall times of <5ns.

The design that I'm working on is a hybrid of these two approaches.

Well,  would you mind discussing this?  Charging up a given capacitor to a certain voltage level establishes its stored energy, E= C x V2 / 2 if you agree.  The charge up time is established by t = R x C.  It is okay that you can take out much more power from this capacitor if you choose the discharge time much smaller than the t charge up time was but the energy remains the one given by the formula, it cannot change.  IT is okay that you can get a very high discharge current from this capacitor for a very short time, the shorter the time the higher the peak current but if the effect of this high peak current does not create something useful to have a kind of "gain", then you are left with the same energy the capacitor have had (minus losses).  And the capacitor has to be charged up periodically of course with energy to have its stored energy which are equal (minus losses) IF there is no "gain". 

The same applies for coils,  they store E = L x I2 / 2  this is what you input with your current.  The inductive kickback (a voltage spike) can only include as much energy as the input current has established if you agree.
IT is okay that you can charge multiple capacitors from a coil at field collapse  but the energy content of this field is a given,  meaning the captured energy content of all the capacitors should sum up to the field energy the input current created in the coil (minus losses).   

A small correction if I may,  you wrote:  "The current continues in the same direction except that it is now reverse polarity compared to the original input current." 
  The current will have the same direction and will have the same polarity (not reversed), ok?  What reverses is the polarity of the created voltage spike by the field collapse if we compare its polarity to the input voltage we switched across the coil to start coil current.  The input current creates an increasing magnetic field (till full saturation) and from the switch-off moment the current starts decreasing hence the field decreases too (the direction of induction in the coil changes if you like). 

So if there is no "gain" obtained somehow in such a circuit, then we are left with COP < 1 performance,  IMHO.

Please look at these posts at the other forum where member Mem built a Don Smith-like circuit and asked whether he had ou ?  https://overunity.com/19484/high-amps-from-3-volts-is-this-an-ou-circuit/msg578321/#msg578321

And I suggested him to attempt looping it, hopefully he will do it.   From his setup, the only hope I can see to have any "gain" (I mention above),  hence a successful looping is if the spark gap attracts free ions, electrons from the air to increase output power hence energy... as turns out maybe happening from one of your links' paper you referred to the other day.

Gyula 
   

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How well would this work as a TF Core?

https://www.ebay.co.uk/itm/204118425910
   
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How well would this work as a TF Core?

https://www.ebay.co.uk/itm/204118425910

Hi lou  (ex Renaissance Rising),

What you mean on TF ?   Maybe Toroidal Ferrite? 

If so,  then it would have a tiny air gap between the facing surfaces of the C cores which a normal toroidal core does not have.  But this may not be necessarily a drawback in most applications, so it depends.
The cores you linked to seems to be scavenged from television line output transformers, operational frequency was around 15-17 kHz,  and around 25-35 kHz if they served in computer monitors. 

Gyula
   
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Hi lou,

Referring to the "Tiny Generator"  https://www.youtube.com/watch?v=OKZEoL5zvFU  circuit, you wrote this:

The 1N5408's are on the "negative" side of the coil, cathode toward the coil..
So I reckon that flyback "travels the same way" as the current used to invoke it. (provided a return to source is present)


But a return to the source (which is the 12 V drive battery) is not present from the flyback pulse point of view: the IRF840 is switched off and the HV spike appears across the coil i.e. between the Drain of the MOSFET and the positive rail of the 12 V drive battery. And the polarity of the spike would be the opposite of that of the drive battery because the spike would have its positive peak appear on the Drain pin end of the coil and its negative polarity would be on the positive 12 V drive battery rail.
So what was written in the text as the "charging current also passes through the 12 V drive battery" is not correct.

 Note that the mentioned 600 V spike amplitudes could happen when the 3x 12 V charge batteries would not be connected, this situation should be avoided because the 500 V rated MOSFET switch could burn from the 600 V spikes. Under the normal charging operation the 600 V spikes are clamped by the 3 series batteries to below 40 V or so and the voltage difference provides their charging current.

Would like to show you a video where the flyback pulse was also said to be charging back the 2 input batteries. The original claim was that in case a coil is added in series with a resistive heater element and the current is switched on and off for the heater, then the flyback energy from the coil is recovered at the drive batteries in the circuit shown in the video. https://www.youtube.com/watch?v=CYW_TYIBkgA

Please read the long comment from "Infineon Experiments" under the video, starting with "This circuit cannot recharge the batteries as the potential difference of RL is shunted across D1. All of the energy stored in the magnetic field will be dissipated in D1 and RL."

Gyula   
   
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Well,  would you mind discussing this?  Charging up a given capacitor to a certain voltage level establishes its stored energy, E= C x V2 / 2 if you agree.  The charge up time is established by t = R x C.

I'll put something together to try to explain my point of view about this when I have 30 mins spaqre, but I think we're going to need to go a bit 'off piste' with my explanation because it doesn't follow conventional thinking.

A small correction if I may,  you wrote:  "The current continues in the same direction except that it is now reverse polarity compared to the original input current."
  The current will have the same direction and will have the same polarity (not reversed), ok?  What reverses is the polarity of the created voltage spike by the field collapse if we compare its polarity to the input voltage we switched across the coil to start coil current.  The input current creates an increasing magnetic field (till full saturation) and from the switch-off moment the current starts decreasing hence the field decreases too (the direction of induction in the coil changes if you like).

Of course, you are right. I was thinking about voltage only when I mentioned about the polarity.

Quote from: gyula
The inductive kickback (a voltage spike) can only include as much energy as the input current has established if you agree.
IT is okay that you can charge multiple capacitors from a coil at field collapse  but the energy content of this field is a given,  meaning the captured energy content of all the capacitors should sum up to the field energy the input current created in the coil (minus losses).

Imagine you had 2 coils (L1 & L2) in separate circuits, with L2 wound over L1. L2 has a diode in it's circuit such that it opposed the creation of the magnetic field from L1. If a current was passed through L1 then it would create a magnetic field, but L2 would not do anything because of the action of the diode. Lets say that the current in L1 is now interrupted. L2 would now conduct from the collapsing magnetic field because the diode is no longer reverse biased.

I think it is well understood that a magnetic field cannot be shielded by any material presently known to man. With this in mind, what would happen if we had more coil & diode circuits similar to L2? Would the magnetic field somehow weaken due to the presence of these additional coils?


Hector (of EV Gray Yahoo group fame) said this (somewhat cryptically if I must say so!):

Quote
Capacity value  Must be decreased. With frequency  increase ...... as is inverse to impedance increase with frequency .

I think what he means is that if you are increasing frequency, then you can decrease capacitance and still maintain the same energy output.

I found the following quotes about the EV Gray motor quite interesting.

Quote
The development of high voltage (2000 to 3000 volts) D.C. power for operation of the E.M.S. motor incorporates a specialized high efficiency, high frequency inverter developed by EVGRAG ENTERPRISES. The operating frequency is 6000 cycles as compared to the 60 cycle line power or A.C.
...
EVGRAY ENTERPRISES
Signed: Richard Hackenberger.
From http://www.tuks.nl/wiki/index.php/Main/ColeHackenbergerPowerSupply

Quote
As Lens activated the battery, a voltmeter gradually rose to 3,000 volts, At that point, Gray closed a switch and there was a loud popping sound. The top magnet hurled into the air with tremendous force and was caught by Hackenberger. A terrific jolt of electricity had propelled the top magnet more than two feet into the air --- but the magnet remained cold.

"The amazing thing", Hackenberger said, "is that only 1% of the energy was used --- 99% went back into the battery."

Gray explained, "The battery can last for a long time, because most of the energy returns to it. The secret to this is in the capacitors and in being able to split the positive."
From http://www.rexresearch.com/evgray/1gray.htm
   
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So, this is what I'm thinking.

If you 'compress' a wave by doubling the frequency and amplitude, then the energy of that wave increases with the square of the amplitude, so the energy is quadrupled.

Quote
The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.
From https://www.physicsclassroom.com/class/waves/Lesson-2/Energy-Transport-and-the-Amplitude-of-a-Wave

Here's a chart I put together in Excel to illustrate. It shows 3 waves - a reference point (1Hz) and then a doubling of the frequency and amplitude of wave 1 (2Hz) and another doubling of the frequency and amplitude of wave 2 (4Hz).

You can see how the energy increases dramatically with every doubling of the amplitude.



In a 'disruptive discharge' of a capacitor it stands to reason that the energy of the capacitor will be discharged in an extremely small time period. This causes a wave of large amplitude in a short period of time. If you discharged the same energy over a longer time period then the amplitude of the wave would be smaller, and therefore the energy will be lower accordingly.

My theory is that if you discharge a capacitor in a small time period, and do this at high frequency, then the energy produced will be much more than if you did the same over a longer period at a lower frequency.

This calls for a device split into two halves that works at two frequencies. The generator frequency and the output frequency. The generator frequency should be much higher than the output frequency. Referencing Hector's post about reducing capacity when frequency increases, the generator capacitor should have a small capacitance. The output capacitor should be discharged at a lower frequency and therefore should have a large capacitance.

Here is a rough sketch of what I'm thinking:

   
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For the output part, I am going to step down the voltage using a capacitor divider transformer. I'm going to do this using a series charging & parallel discharging arrangement.

Example:

Take 10x 100uf 1000V capacitors.

Arranging them in series raises the max voltage to 10kV, but reduces the total capacitance from 1000uF to 10uF. Each individual capacitor can hold 100uF @ 1000V when charged at 10kV in series. The stored charge is 0.1C and the stored energy is 500J.

Once charged, switch from series to parallel.

Arranging them in parallel gives you 10x 100uF charged to 1000V, each having a stored charge of 0.1C and 50J stored energy, giving a total of 1C and 500J.

Now discharge the capacitors in parallel through the load.

Notice that the charge increased by 10x when switching from series to parallel.

Quote
The SI defines the coulomb in terms of the ampere and second: 1 C = 1 A × 1 s.

1 Coulomb is 1 ampere-second (1 C = 1 A.s)
1 amp = 1 Coulombs per Second (1 A = 1 C/s)

If the charge (in Coulombs) increases, then is this not a current amplifier?

The number of capacitors determines the multiplication factor.
   

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Golden research material ! Thankyou for sharing. Circuit diagram looks great.

I would like to lay it out in such a way that every component is easily accessible, as simple and neat as possible, for ultimate clarity. Similar to what Don did but more compact. In a small steamer trunk or similar.
Gather and optimize all components according to the plan prior to installation, then tweak "in situ"

Independently powered, galvanically isolated, non contact probes / meters throughout to avoid any interference.

This is how I imagine going about it anyway.. "Corner the variables" and eliminate guesswork wherever possible

Aim for a loop right off the bat - seems the most direct way to start and "kills 2 birds with one stone" so to speak
Why wouldn't that be the first priority if such a thing can at all be achieved?
   
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I would like to lay it out in such a way that every component is easily accessible, as simple and neat as possible, for ultimate clarity.

Aim for a loop right off the bat - seems the most direct way to start and "kills 2 birds with one stone" so to speak
Why wouldn't that be the first priority if such a thing can at all be achieved?

Yep, total clarity and transparency is what I'm aiming for. Leave no doubt in the minds of people wanting to replicate, if it comes to that. I'll list all components with part numbers etc.

I'm designing my system to be looped from the get go. As you say, it kills two birds with one stone and if it did work then it would provide validation that the system is OU.

I forgot to include the looping part in my circuit diagram. I'll revise it to add some circuit elements to provide energy to the main capacitor to recharge from the output. The battery and step up circuit is only designed to be used once to start the device. I guess you could replace that with a hand crank generator or small solar panel if absolutely no battery power was desired.
   
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...
Imagine you had 2 coils (L1 & L2) in separate circuits, with L2 wound over L1. L2 has a diode in it's circuit such that it opposed the creation of the magnetic field from L1. If a current was passed through L1 then it would create a magnetic field, but L2 would not do anything because of the action of the diode. Lets say that the current in L1 is now interrupted. L2 would now conduct from the collapsing magnetic field because the diode is no longer reverse biased.
...

Is this what you mean?
The attached pdf file might be useful.



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Is this what you mean?
The attached pdf file might be useful.

Yes, exactly that. A flyback transformer, except with more than one secondary. Maybe air core rather than ferrite. What would happen?
   
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What would happen depends on how the circuit is set up and operated.
The flyback winding will provide some extra when used in a circuit like you proposed, especially when the primary excitation current is not wasted to ground.

For example, I did this experiment before finding the pdf attached in my last post, so the trafo wasn’t properly designed as a flyback type. Still, after correcting for actual measured cap capacitances it showed apparent Cop ~ 2. But take note of the long time for the charge to accumulate, about 220 ms. I think this was due to my amateur design and the subject needs further exploration.

See https://www.overunityresearch.com/index.php?topic=4295.msg99383#msg99383



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'Tis better to try and fail than never try at all
   
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Here is my revised circuit with looping.

   
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Ifarrand
Quote
Imagine you had 2 coils (L1 & L2) in separate circuits, with L2 wound over L1. L2 has a diode in it's circuit such that it opposed the creation of the magnetic field from L1. If a current was passed through L1 then it would create a magnetic field, but L2 would not do anything because of the action of the diode. Lets say that the current in L1 is now interrupted. L2 would now conduct from the collapsing magnetic field because the diode is no longer reverse biased.

I think it is well understood that a magnetic field cannot be shielded by any material presently known to man. With this in mind, what would happen if we had more coil & diode circuits similar to L2? Would the magnetic field somehow weaken due to the presence of these additional coils?

I found it's normally a catch 22 scenario.

If we use let's say 6 air coils the induction is weaker in each coil because the magnetic field is reduced following the inverse square law. If we use 6 iron cores the source field is concentrated in each core but each is less than 1/6th the source field. That's only the start and the moment each coil starts conducting a current it's field opposes the field which induced it.

I found there are other possibilities falling outside the normal process of induction. Here one has to understand the process of induction well enough to know it's limitations. For example, the energy transferred by mutual induction is solely defined by the rate of change and magnitude of the source field. This is dependent on the rate of change of the source current. This is how all mutual induction normally works.

However if the primary source current established a changing magnetic field coupled with the secondary. Then as the primary field collapsed it used this energy to enter a superconductive state this is a different scenario. Super conduction doesn't attract/repel magnetic fields it expels all magnetism. Now were talking about an already established magnetic field being displaced by a third force changing the total rate of change. In effect, we don't simply expand and contract the fields which normally happens in mutual induction but expand and displace them.

Realistically, all we have to do is understand exactly how mutual induction works and then not do that. Do not do or allow what should normally happen to take place. By changing the rules we change the process and the rate of energy transfer.

AC

 






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Comprehend and Copy Nature... Viktor Schauberger

“The first principle is that you must not fool yourself and you are the easiest person to fool.”― Richard P. Feynman
   
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What would happen depends on how the circuit is set up and operated.
The flyback winding will provide some extra when used in a circuit like you proposed, especially when the primary excitation current is not wasted to ground.

For example, I did this experiment before finding the pdf attached in my last post, so the trafo wasn’t properly designed as a flyback type. Still, after correcting for actual measured cap capacitances it showed apparent Cop ~ 2. But take note of the long time for the charge to accumulate, about 220 ms. I think this was due to my amateur design and the subject needs further exploration.

See https://www.overunityresearch.com/index.php?topic=4295.msg99383#msg99383

Thanks Cadman. I just read your thread and it sounds very intruiging. Did you get any further beyond the last post in the thread?
   
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Yes, I played with the circuit configuration and tried to take the energy off the end like your schematic does, in principle anyway but not with the same circuit arrangement. It also had several cheap digital current & voltage sensors hooked up to the input and outputs with the load being a 12Vdc motor and they clearly showed an apparent OU happening. Not having a good scope at the time I was ready to replace the digital meters with analog meters when the circuit blew up all the fets, again. Disgusted with my lack of solid state abilities, it’s been shelved until I get better with electronics.

But, the experience was educational and well worth the effort. Now I know for sure that ‘more out than in’ is possible with a pulsed flyback transformer as an energy multiplier just by not throwing away the primary impulse out of the trafo but combining it with the secondary instead.

In general it looks like you have the same sort of idea and I hope you can do much better using your superior skills.
I wish you all the success in the world with it.



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Hi Lee,

Thanks for your answers and the interesting pieces of information.
 
I am open to accept "rules bending or violation" but to change my views it needs facts and so far I have not come across nor seen any 100% convincing results that prove
a device can self run (its output is looped back to its input) or correct measurements are done on it.

I agree with Allcanadian on the limitations of mutual coupling but no idea how he means the superconductive state,  at what cost a third force is created to displace the collapsing field.   Nevertheless, it sounds interesting.

I used to follow Hector's posts in the early yahoo EVGray forum and certainly many useful info were shared on making 3 phase motors run from single phase by using
capacitors (and other components).  Off the shelf 5 or 6 HP motors were able to run with 10 -20 W input power but the moment the motor shaft was loaded,
the initial low input power (achieved by motor coils tuning and phase shift) went up while RPM went down with low torque remaining, this is what I can recall. Maybe I do not remember well.

You refer to this link https://www.physicsclassroom.com/class/waves/Lesson-2/Energy-Transport-and-the-Amplitude-of-a-Wave  and you quoted this from it:
"The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude,  the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy."

This sounds very good but let me note: in my understanding it is you who has to provide energy (i.e. it costs you) to increase the amplitude of a wave i.e. its energy.  Is not energy conserved here?
IF not, where would the extra come from?   I do not think the writer of the above link on energy transport and wave amplitude supposed the amplitude doubles by itself? 

But I do encourage you to carry on and if I can help I will do of course.

Gyula
   
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Yes, I played with the circuit configuration and tried to take the energy off the end like your schematic does, in principle anyway but not with the same circuit arrangement. It also had several cheap digital current & voltage sensors hooked up to the input and outputs with the load being a 12Vdc motor and they clearly showed an apparent OU happening. Not having a good scope at the time I was ready to replace the digital meters with analog meters when the circuit blew up all the fets, again. Disgusted with my lack of solid state abilities, it’s been shelved until I get better with electronics.

But, the experience was educational and well worth the effort. Now I know for sure that ‘more out than in’ is possible with a pulsed flyback transformer as an energy multiplier just by not throwing away the primary impulse out of the trafo but combining it with the secondary instead.

In general it looks like you have the same sort of idea and I hope you can do much better using your superior skills.
I wish you all the success in the world with it.

I'm glad to hear to you have had some promising results with your set up, it gives others encouragement that there is an achievable goal at the end.

I was an electronics novice 18 months ago, but took the opportunity during lock down and used the extra time I had working from home to get stuck into electronics & PCB design and learn everything from scratch. I mean everything! I remember reading Patrick Kelly's A Practical Guide to 'Free-Energy' Devices and wondering what everything meant. What's a diode, what's a transistor and so on. It was completely foreign to me and very difficult at first, but slowly over time I began to understand the various components and what they did.

Most things in life are generally achievable through hard work, perseverance and tenacity, so please don't give up on electronics just yet.

I'm doing this for us all. Any success I might have is everyone's success. I'm standing on the shoulders of giants.
   
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I am open to accept "rules bending or violation" but to change my views it needs facts and so far I have not come across nor seen any 100% convincing results that prove
a device can self run (its output is looped back to its input) or correct measurements are done on it.

I absolutely agree with you there. I wouldn't hope to attempt to change someone's mind on the established status quo without some compelling evidence (that has been peer reviewed) to support my claim. Extraordinary claims require extraordinary evidence as someone once said. That's why I'm so keen to get measurements correct so that I don't go down any blind alleys.

Quote from: gyula
This sounds very good but let me note: in my understanding it is you who has to provide energy (i.e. it costs you) to increase the amplitude of a wave i.e. its energy.  Is not energy conserved here?
IF not, where would the extra come from?   I do not think the writer of the above link on energy transport and wave amplitude supposed the amplitude doubles by itself? 

If the source (coil or capacitor) is disconnected from the supply at the point of discharge then is this still the case? Do we still pay for the extra energy released in a shorter, sharper discharge? The way I see it is that we accumulate energy in a capacitor over time and then discharge it all at once. Tesla pointed out the similarity in action with that of a pile driver.

When a lawyer asked him during an interview in 1916 if the effects “depend upon the suddenness of the discharge”, he replied:

Quote
Yes. It is merely the electrical analogue of a pile driver or a hammer. You accumulate energy through a long distance and then you deliver it with a tremendous suddenness. The distance through which the mass moves is small—the pressure immense.

Here are some other relevant Tesla quotes:

Quote
The effects which are produced by currents which rise instantly to high values, as in a disruptive discharge, are entirely different from those produced by dynamo currents which rise and fall harmonically.

Quote
The general plan is to charge condensers [capacitors], from a direct or alternate-current source, preferably of high-tension [high voltage], and to discharge them disruptively while observing well-known conditions necessary to maintain the oscillations of the current [resonance].

Quote
I charged the condenser with 40,000 volts. When it was charged full, I discharged it suddenly, through a short circuit which gave me a very rapid rate of oscillation. Let us suppose that I had stored in the condenser 10 watts. Then, for such a wave there is a flux of energy of (4 x 104)2, and this is multiplied by the frequency of 100,000. You see, it may go into thousands or millions of horsepower.

I found this site really quite enlightening: https://waveguide.blog. This article in particular: https://waveguide.blog/teslas-spark-gaps-literature-review/

Quote from: gyula
But I do encourage you to carry on and if I can help I will do of course.

Thank you for your kind words and support. I'm very greatful for the help and advice that you've given me so far.
   
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Hi Lee,

You wrote:
Quote
"If the source (coil or capacitor) is disconnected from the supply at the point of discharge then is this still the case?
Do we still pay for the extra energy released in a shorter, sharper discharge?"

Yes, unfortunately it is still the case. To increase the amplitude of a wave to increase its energy, you have to invest energy. The very high spike amplitude
created across a coil at the current switch-off moment  or the very high current coming from the sudden discharge of a capacitor is still the case because the increase of
the amplitudes is involved in a short time and energy is power times time.  I.e. even if the hugh spike (or current) would create high power in a load it would be
peak power lasting for a short time.
No extra energy can be released in such processes: how would energy release extra energy?  The process involved in fission or fusion
reactions can release energy but the atomic structure of the materials involved changes. Or during transmutation, energy is also released but none of these processes is
involved here.

The quote from Tesla includes answer too: 
"It is merely the electrical analogue of a pile driver or a hammer. You accumulate energy through a long distance and then you deliver it with a tremendous suddenness.
The distance through which the mass moves is small—the pressure immense
."

He spoke about the same energy applied within a shorter time.
Putting this otherwise: he charged up a capacitor from a generator using certain power,  it involved a certain generator voltage, and charging time, (the latter was established by the capacitor value and by all the resistances involved inside the charging circuit). The power times the charging time established a certain stored energy. Then the power invested was released in a very short time: the shorter the time the higher the power was available.

You quoted Tesla further on:

"I charged the condenser with 40,000 volts. When it was charged full, I discharged it suddenly, through a short circuit which gave me a very rapid rate of oscillation.
Let us suppose that I had stored in the condenser 10 watts. Then, for such a wave there is a flux of energy of (4 x 104)2, and this is multiplied by the frequency
of 100,000. You see, it may go into thousands or millions of horsepower.
"

Well, horsepower is power, not energy...  He did not say he multiplied energy, he multiplied power. Unfortunately a big difference.

This is how I understand Tesla.  I respect your or anyone's opinion if it is different.

Gyula
   

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"It is merely the electrical analogue of a pile driver or a hammer. You accumulate energy through a long distance and then you deliver it with a tremendous suddenness.
The distance through which the mass moves is small—the pressure immense."


I really like that quote .. as a species, our brains have evolved a relatively firm grasp on mechanical concepts, by any reckoning, through necessity

I suspect that's why Tesla would explain it that way, so his audience might have a hope of understanding.

If it's appropriate to metaphorize / apply a physical 3D analogy to a given electrical phenomenon as is often done, then surely some comparable mechanism exists in the tangible, observable world that we could model a circuit like this directly off?

Don Smith gave his thoughts on electron spin in the "Tesla Symosium" (Not sure of the no.) - that happens regardless of our actions - as does the earth spin (a cliché statement, I know)
As will a brass door handle in an old house shock you with no readily apparent reason besides that of someones' "yeah don't you know about static electricity??" Well it seems no one really knows how that charge got there..
Please do correct me if I am mistaken.

I have read / heard that the capacitor is all that's important .. This could be made to work with just a capacitor?
Not sure what to make of that but it's relevant for sure?

We know higher voltage and higher frequency usually yields more exciting results in any HV experiment, and lower current draw is always a primary goal too; I personally am most interested in finding what exact and specific part of Don's system allowed the "pumping" to occur.

I will have to watch through those Don Smith interviews again soon.
I think he left us just about enough to make something work, and like others, see the resemblance in other "Radiant energy" devices.

The terminology used by different inventors / developers makes matters all the more confusing IMO.
Hence the need for analogizing  .. A very powerful mental tool imo
   
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Posts: 271
I've been busy building a bunch of MOSFET driver PCBs. It's surprising how much of a time sink it is soldering components to a board!

I'm aiming for 2000V operating voltage / 1MHz frequency for the front end / generator part of the system, and 240V / 50Hz for the output.

To this end I'm going to use:

  • 1x driver board with a 2000V, 0.075Ω, 34A cont., 74A peak MOSFET for the front end of the system
  • 1x driver board with a 2000V, 0.075Ω, 34A cont., 74A peak MOSFET for the looping / recharge part of the system
  • 2x driver board with a 2000V, 0.024Ω, 89A cont., 189A peak MOSFET for the output part of the system

The output part will handle 378kW (!) peak (2000 x 189). That's pretty scary, but in the context of EV chargers it's in the same ballpark. Tesla superchargers max out at 250kW currently.

The front end / generator part will discharge 4x 6.8nF (27.2nF) silver mica capacitors in parallel into the output capacitor (500uF) via a low self inductance coil (size TBD). I might not need the FWBR, but might add it in to harvest / snub the inductive kickback.

The output MOSFET switches will discharge the output capacitor into an isolation transformer 50 times per second, which will step down the voltage from 2000V to 240V, and raise the current by 8.33x. The output will be a pure sine wave which will be generated by the Arduino using an sPWM algorithm.

That's the plan anyway. There are still plenty of unknowns so this isn't set in stone and is subject to change as I develop a better understanding.
   

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Posts: 321
Be the change you wish to see in the world
Awesome - please keep us updated. Wishing you great success 
« Last Edit: 2023-06-01, 22:55:54 by lou »
   
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Posts: 271
I forgot to add that the TO-247 MOSFETs are limited to around 70A in practise due to the leads. Any higher and they would melt.

I'm not entirely sure why MOSFET manufacturers list amps in excess of the package limit.
   
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