@ ION
We agree to disagree as gentlemen I hope.
Oh yes, absolutely, I wouldn't have it any other way.
As a scientist I would ask how much radiated power and in what frequencies bands or spectra is available and at what distance from the power lines around SM's home? When you can answer that question with real data, I will take your theory more seriously.
I assumed you saw my postings and calculations I posted a few times in the past? I guess not, but no problem, I can do it again.
Considering the inverse square law, a spherical radiation pattern (not beamed power) how much loss do you calculate from a setup like that over say 20 meters? How much power is required in the transmitter loop to supply a kilowatt 20 meters distant?
First of all, I'm not concerned with losses in the "transmitter" when the transmitter is the power lines, I don't have any control over that as an energy harvester. I’m just concerned with the fields I sense at my location, regardless of where they come from. But I know where they come from and that’s what seems to be the problem here. Second of all, we are not dealing with RADIATION and the INVERSE SQUARE LAW, that only applies in the FAR FIELD, that's RF stuff. What we are dealing with is near field coupling via the magnetic fields, as opposed to electric fields like Tesla wanted.
The noise from power lines is broadband, very low in power, is damped by all the resistive loads, and cannot possibly deliver a kilowatt at 20 meters or we would all be fried like chicken from it.
First of all: I agree, the Magnetic fields we experience without a RESONATOR present are weak fields. When we bring a RESONATOR into the field, THAN the fields build up to high levels. The build up in the reactive fields is what ENABLES a LARGER POWER TRANSFER AND COUPLING TO THE SOURCE. This is what I was trying to explain to ltesung888, about his sound resonator experiments, it's very similar.
Second of all: The reason we are not fried like chicken, is because we are utilizing the MAGNETIC FIELD. It is however possible to resonate and receive the electric field like Tesla wanted. But that's a no no, very dangerous. Magnetic fields are better because at low frequencies they are not easily shielded by conductors because the skin depth is larger with lower frequency, but ferromagnetic shields will do the trick.
So I repeat, give me the power and frequency spectra of the SM power lines at a distance of 20 meters. Then maybe I can change my mind.
I provided the spectra and the field strengths and calculations but you must have missed it but I can do it again.
Where I live we have high power lines from the Limerick Nuclear plant passing right over a local park. There are bleachers for the ball field nearly directly under the power lines. The bleachers are grounded because of a slight static charge that builds on them from the power lines. No one is fried when they watch a game. I have been there with equipment and have not measured anything beyond millivolts AC or DC.
Yes, the levels are small, but when amplified with a high Q receiver, those levels can build up to high levels like I show below. That's what I'm trying to tell you guys. That's the beauty of high Q resonators, if there is a field present from whatever source, we can couple to it and receive it’s energy. But the energy source at 5 kHz or 6 kHz is not from some unknown place, AS I FOUND OUT. It’s coming from the power lines like I showed you guys in the past. It’s the power line harmonics from switching equipment, or maybe something that coupled to the power lines and flows on them, but the reality is that it’s there and SM is tapping into it. This point is really not debatable, if he is telling the truth when he said 5 or 6 kHz and I can see that frequency on the spectrum taken at the mansion from the power lines, its obvious and I know and draw the conclusion that it is due to the power lines. I’m not sure what other conclusion I can draw? What are your suggestions? Steven even says he’s TPU is a receiver and is tuned to a magnetic frequency and "converting" it's energy, are we not going to believe him? Just think about it and let it sink in, that's all I can say.
Ok, just for you ION: Let me do this again, I want to show you some sample calculations to build up your confidence. I will first calculate the magnetic field density at a distance from a current carrying wire or power line, than deal with the Receiver and assume a certain Q that I suspect is being used by SM.
TRANSMITERAssume a current on an infinite wire as an approximation, since we assume we are relatively close to a long power line. Than, the magnetic field density B, at a distance R, is given by:
B = (4 pi 1e-7) I / (2 pi R)Assuming the current, I = 100 amps (which is conservative for a power line), at 20 meters away we get close to 10 micro Teslas. Sounds very small right? But hold on there is more, let’s look at the receiver now.
RECEIVER If the frequency is 5.5 kHz let’s say, we can calculate how much voltage is induced into an OPEN CIRCUIT loop. After we calculate this, we will than assume we can tune the loop with a capacitor and make it resonant, and we'll assume a Q = 100, for starters. However, I suspect the TPUs are using acoustic vibration as the resonator mechanism and as such these have Q factors in the 10 000 range.
Here we go: This is the equation we’ll use to calculate the induced voltage due to a change in the magnetic flux phi = B x Area of loop. For simplicity we’ll assume Area =1 m^2 , and the number of turns in the loop N=10.
V = -N dphi/dt = - 10 * d B/dt,If we are only interested in one particular frequency, or sinusoid, that we'll tune into, than the magnetic field density as a function of time is described by B = B_amp x sin(2pi f t). Differentiating we obtain:
dB/dt = B_amp x 2pi f x cos(2pi f t), we're only concerned with the amplitude from now on, so we’ll drop the cosine. Also note that upon differentiating, the frequency now plays a role. Some of you might quickly realize that it’s beneficial to do this type of wireless power transfer at higher frequencies, and that is correct, but there are implications I won’t go into. Let’s proceed by substituting B_amp = 10 miro T, and f = 5500 Hz
Vpeak_oc = 10 * (1e-5 x 2 pi 5500) = 3.5 voltsRemember, this is the OPEN CIRCUIT voltage, no resonance implemented yet!
If we implement resonance, and let's say we have a tank circuit with a Q = 100, the magnification factor, which is very easy to accomplish just with LC circuits alone, we obtain:
Vpeak = Vpeak_oc * Q = 3.5 x 100 = 350 volts !But we know that volts without current means nothing, so how much current can I draw? As few of you know, if I load the coil I change the Q, and I lose what I'm after, but there are techniques to minimize this and obtain an optimal results, by impedance matching. From my experiments, I observed that I can lower the Q by a half, and manage to draw significant power, so OK, let's say under load the voltage drops to 150 volts, with a source impedance of 10 ohms, and I can draw 1 amp. The power received is than:
P_avg = (V x I) / 2 = 1 amp x 150 volts /2 = 75 watts (were dealing with peak amplitudes, not RMS, that's why we divide by 2)
But if I load the receiver with a 10 ohm load, equal to the source impedance for maximum power transfer, I can extract:
P_avg = V^2/2R = 150^2/20 = 1125 watts!So, as amazing as this is, imagine that SM has a resonator (TPU) of a Q = 10 000, that’s 100 times greater than what we calculated above. He can than realize an open circuit voltage of perhaps 35 000 volts or 35 kV! This is distructively high! That’s why SM said that the devices have to be tuned
SLIGHTLY OFF FREQUENCY, or else they destroy themselves,
NO KIDDING!
There you have it ION, math for your eyes! If you don't believe the math than I can't realy do much else for you short of a demo. Thanks for the questions, I love to teach! or rather preach! LOL
EM
feature is available which provides a place all members can chat, either publicly or privately.
Author
Topic: The TPU: Was It Real ? (Read 287204 times)
