I guess you did not watch this video I posted on the first page of my topic.
In this video they demonstrate what happens when you have current circulating in a Real super conductor.
They demonstrate the Voltage falls to 0.000
https://www.youtube.com/watch?v=PifnlZigp6c
Cheers mate
Luc
Yes,i watched the video Luc,but i dont think you paid attention to what they did in that video.
What they showed was a complete waste of time and effort.
They clearly state at 5:40 in the video-->to charge the device,we use a 20 amp 5v power supply. Once connected to the circuit,we then submerge the device in liquid nitrogen.
So,it is exactly as i said it is.
First the coil has to be energised,and then you submerge it in liquid nitrogen.
So if the voltage is 0.000 how can there be any power dissipated across the coil? ... please explain where the power comes from.
But the voltage was not 0 when they charged the coil,as the coil was charged before being submerged in liquid nitrogen,and becoming super conductive. So,the power to charge the coil would have been the maximum power that there power supply could have delivered to the coil before it was made super conductive.
The video shows exactly what i said--you cannot charge the inductor once it becomes super conductive,as it will reject any magnetic field that tries to penetrate it.
Even if the voltage was 0 across the coil,it will never be 0 within the transformer of the power supply.
So even if the super conductor dose not dissipate any power,the power supply being used to power up the super conductor will,and it will dissipate the maximum amount of power it is capable of,because you just dropped a dead short across it.
The other video you posted,where the guy has a coil under some flat bar,which is sitting on the scales,clearly shows a massive increase in current draw when he cools the coil with liquid nitrogen to bring the resistance down. Before he cools the coil,there is no arcing of the wire when he touches the coil on the battery. When he cools the coil with liquid nitrogen to reduce the coils resistance,and then connects it to the battery,you can see massive arcing of the wire,which clearly means a massive increase of power input to the coil,as we could assume that the batteries voltage would remain fairly stable between the two tests.
Brad
Never let your schooling get in the way of your education.