That's right.
Take a little hobby DC brushed motor, connect a little incandescent bulb (use one of those GOWs!) to the brushes and turn the armature. Does the bulb get brighter when you turn the armature faster?
QED.
No TK,that is different,as you are also increasing the number of cycles-more magnet passes across the coil per minute-so to speak. We are talking about 1 single pass of a magnet across a coil/inductor. Here is a thought experiment. We have a coil with a FWBR attached to it's output leads,so as to rectify to DC. We then have a cap across the FWBR output,so as to collect the energy produced by the coil. Lets say that the cap is 100uF. Test one We now disconnect one end of the coil from the FWBR,so as we can do an open voltage test. We move the magnet passed the coil as a set speed,and obtain an open voltage across the coil of say 5 volt's. We now hook the coil back up to the FWBR,and move the magnet across that coil at the same speed as the open voltage test,and we end up with-say 3 volts across the 100uF cap. So our coil voltage has been limited to 3 volt's-plus the V drop across the FWBR. Now we replace the 100 uF cap with a 200uF cap. Now,we know that is we pass the magnet across the coil at the same speed as test one,we will not get 3 volt's across the cap. BUT-if we pass the magnet across the coil faster,will we be able to get 3 volt's across the 200uF cap ? Brad
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Topic: Current produced to rate of change of magnetic field within an inductor (Read 31966 times)
