Hi Ren,
Thanks for your comments.
For the impedance matching issue you stated:
Didnt you just say below that the inductive discharges pulse will vary depending on the impedance of the load? Of course it STILL outputs a current/voltage pulse either way, but what is the quality of that pulse? So doesnt the load effect the qualities of that pulse like you said? Cannot the impedance of the primary coil MATCH the impedance of the discharged energy (load)? Would this not qualify as an IMPEDANCE MATCH? ANd of course you are aware that the Monopole motor (all norths out) does produce a sine wave when scoped, despite this being a pulsed DC operation. Does that come into account?
I have another way to explain this one to you, but permit me to hold off on it for now. I'm nearly 100% certain that you know that an impedance match is to get the maximum power transfer from the source to the load. To answer your question above yes, the load affects the quality of the pulse.
You are strong in your convictions and that's great, so I have some follow-up questions to pose to you. What is the output impedance of the primary coil? What is the input impedance of the charging battery load? Where is the match?
For the monopole motor, I am aware that it produces a sine wave on a pick-up coil. You can also see pieces of a sine wave on the drive coil. But beyond that I am not sure were you are going with that and how it relates to impedance matching. If you can clarify that would be great.
Your comments about the dephasing:
By Dephase I mean out of phase. The inductive discharge occurs out of phase from the initial pulse. The inductive discharge cannot draw more power from the source, because it only occurs when the switch opens, and is only connected to the positive terminal of the source.
Okay, sure. I will just add to that statement. When the transistor is on, the drive coil is being charged with energy. Then the transistor switches off and the coil discharges its stored energy into the charging battery. So yes, some energy is stored and displaced in time and released in a new time phase. So going back to your original question yes there are many devices that do this function. People are more familiar with capacitors as energy storage devices but inductors are also perfectly viable energy storage devices. A Joule Thief comes to mind right away.
On Bedini motor pulses:
Yes but you yourself say that the shape of that current pulse will differ depending on the load! If the impedance of the load is very high, the current pulse will be very short. So a pulse is a pulse. Nothing special there? Is that what you are trying to say?
What I am trying to say is that it is worth it to study how and why the pulse shape is formed by a discharging inductor. There is nothing special just like you would say there is nothing special when looking at the pulse shape of a capacitor discharge.
Think about this: You know both caps and coils store energy. The smaller the resistance you connect across the capacitor the faster it discharges. It's common sense. You know that if you short a capacitor out you get a spark, all of the energy is dissipated in a split second. So what about a coil? One more time, there is a symmetrical answer, but it is not common sense and not so intuitive. For a coil, as you increase the resistance across it, the faster it discharges. If you open-circuit the coil, you get a spark, and all of the energy is dissipated in a split second. So you can see the symmetry one more time.
What happens when we explore the symmetry in the other direction? It's simple and easy and makes sense: If you open-circuit a capacitor then it doesn't discharge, it simply keeps on storing its energy. If you short-circuit a coil, then it doesn't discharge, it simply keeps on storing its energy.
My question about the spikes going away:
For example, why do the voltage spikes go away when you connect your charging battery? I bet you that the vast majority of Bedini experimenters can't answer that question. That's why this thread is here, the question is not being answered on any other threads as far as I can see.Because you have changed the load impedance
Absolutely correct. Following up on the stuff that I said above: If the load impedance is zero, then there is no voltage spike at all! The higher the load impedance, the higher the voltage spike. So if you put a 1-ohm resistance as the load, then you can look at the voltage spike on your scope and measure the initial current flowing through the coil. You can change that to a 10-ohm resistance, and you will still measure the same initial current going through the coil, but this time the voltage spike will be shorter in duration.
A fun follow-up question, and I already asked it before: What is the load impedance of the charging battery?
MileHigh