Hi People,
Sorry I have not seen the vid:
http://piter.tv/video_clip/25503/My Malwarebytes (Pro) gave me a warning.
Most Russian web sites are crammed with nasty Malwares. No?
Should be a cultural fad.
BTW, "Nasty Malwares" is a pleonasm. No?
Sorry also, I do not fully catch what this very Russian CCT is about?
Some kinda self sustaining stuff?
In that case, and for the fun of it, I have one vid:
"Self-powering / resonating circuit with 555 timer chip - Possibly free energy"
http://www.youtube.com/watch?v=cD_Bwwvlc3ICircuit Simulator from falstad.com
I have "replicated" the proposed CCT in the vid.
Here is the picture:
It works! I mean: the simulation works.
Of coarse, this is just a mere simulation with, I guess, "Official Science Equations".
This simulator must have a bug and/or is not able to deal with sneaky circuits.
It indeed, have some bugs.
If you are too tricky, the simulator gives you a nice "convergence failed" error and stops.
Anyway, a lot of people are claiming non conventional behaviors when playing with "real" trafos. No?Gwella soƱjou a-berz Jean.
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Huge PS:
About "Official Science Equations", most of time, the textbooks are telling half of the story and
do not take into account the 'parametric' aspect of it.
g = d(M.v)/dt. M is assumed to be constant. Assuming M *not* to be constant leads to very interesting equations.
You can consult 'Ronald D. Pearson' and 'Ove Tedenstig'. Google is OK.
v = d(L.i)/dt. 'L' is assumed to be constant. It has not to be so.
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In a nutshell:
'Parametric' is when you change the rule of the game when this very game is playing.
Not fair? Indeed! French (f') politicians recently tried this. They moved back.
In 'OUR' case is it just to achieve 'OU'. No?
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Derivations *not* of my own:
W=qV
P= dW/dt = d(qV)/dt = dq/dt.V + q.dV/dt = I.V + q.dV/dt.
P = P1 + P2
P1 = I.V ; P1 is just half of the story
P2 = q.dV/dt
Now, V=Q/C
Suppose that the capacity fluctuates in time: DC/dt <>0 and the charge Q is constant. dq/dt = 0.
You eventually get P1= I.V = dQ.V/dt = 0
and P2 = -V^2.dC/dt
Sorry for any transcription error.
I can post the scan of the paper if you are interested in.
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My claim is that 'OU' is still in the "Official Equations" should we:
- use the full equations.
- take into account the time.
For this, you can consult "Claus Turtur", a German Scientist who is most of time (precisely
) over my head
but not over my intuition. Google is OK too.