Not if I can help it. LOL. The controls that can further validate this 'effect' are certainly NOT dependant on the application of a capacitor MileHigh. To generate the initial supply - that first cycle of imbalance - must come from a material that is innately imbalanced - such as an electrolyte. Because when it discharges it does not discharge to a zero volt condition. A capacitor does. How would you establish that resonating or rhythmical condition of resonance without a continual applied and opposing voltage? I've seen this argued - over and over. It makes me sick. A capacitor IS NOT THE SAME THING AS A BATTERY SUPPLY. All it does is stores charge and then it discharges charge. And if you put any capacitor in series with that circuit it would only probably manage to interfere with that required relationship between the source and the material in the resistor. In fact. I couldn't even be bothered to test this - it's that irrelevant.
Rosemary You can believe whatever you want to believe Rosemary. I never said the capacitor has to discharge to a zero volt condition. I said the opposite, you would have to supply current to the capacitor with a bleeder resistor to maintain its output voltage. For the purposes of your test, the large capacitor would look like a "better battery." The large capacitor and the battery would look like essentially the same to the circuit, that being a source of potential difference to push current through the MOSFET switch and the load resistor. In your blog you say this: It's the same circuit that we've always used - except that we're using a standard immersion element as our load resistor and we're driving the MOSFET with a functions generator. It seems to afford us much better control than the 555. So if I understand you correctly you don't need a battery to establish a "resonating or rhythmical condition of resonance" anymore because you are using a function generator. Note the function generator is also supplying power to the circuit. I don't believe that there is a "required relationship between the source and the material in the resistor." You would have to provide some supporting evidence demonstrating that that statement is true. If you really wanted to you could put a series resistor of something like 0.05 ohms between the large capacitor and the load to emulate the impedance of the battery you are using. You would have to measure the battery's output resistance beforehand to do that. You could check the waveforms between the two setups on the DSO and you could expect that they would be nearly identical. In all likelihood you would not be able to distinguish between the DSO waveform recordings for the capacitor vs. the battery-based setup. The advantage to using a large capacitor for a measurement technique is that it eliminates the need to use a fancy expensive DSO to make precise power consumption measurements. Using a capacitor overcomes the inherent limitations of the DSO related to measuring very high-frequency signals including sampling errors, aliasing, and probe positioning. The large capacitor and the battery would "look" essentially identical to the MOSFET and load resistor, and the circuit would perform in an identical fashion for all practical intents and purposes. Anyway, this is off topic, I will be waiting for the results of your testing. Just a reminder, if you don't summarize the power-in vs. thermal power-out measurements in your report like you failed to do last time then your report will have no credibility. MileHigh
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