Smudge, Thank you for your input on this, so just to be clear on this, TinMan and I were both right and we were both wrong. I was wrong on the minimum and maximum CEMF/BEMF, had it backwards in my old memory and TinMan was wrong about the CEMF/BEMF being in parallel with the source, it is actually in series with the source. Is this correct or am I still wrong? I really would like to come to a consensus on this matter for everyone to understand this stuff.
I am still not feeling right on the naming convention CEMF/BEMF because it happens on both current rise and current fall with AC and DC. One reduces and one adds to the AC signal. I think? Should they both be called the same name, I believe it is rather confusing? I don't know the answers, but again we should nail this stuff down.
Respectfully
Room
How close do you wish to look Room?.
First i must say the value of the EMF and CEMF are measured in volts,and volts shows us a polarity,where we have 0,ground,negative as a reference point to measure the value of the EMF.
So,the CEMF has the same polarity across the inductor as that of the applied EMF, + to +,and - to -.
Now,in relation to Smudges comment,and most accepted ,is this-->
So at T=0 the initial current is 0Depending on how close you wish to look,and how accurate you wish to be,the stated in blue is actually incorrect.
At T=0,there is an instantaneous rise in current which come before or at the rise of voltage across the inductor.
The value of this current,and it's time duration depends on the configuration of the inductor it self. The value of this current at T=0 can be greater than half that of the steady state current through the coil after the 5th time constant. This instant rise in current is the self capacitance of the inductor being charged. This has a side effect,that being the CEMF across the coil rises to a greater value than that of the source EMF. Just after the capacitance has been charged,the resultant CEMF that now has a higher value than that of the applied EMF makes the inductor now act as a negative resistance,where the inductor becomes the source for a short time.
So now,at this point in time,our inductor is sending energy back to the source.
This is the area i am researching ATM in another thread,where there is a tight capacitive coupling between the primary and secondary of a transformer.
But like i said,it depends on who you wish to believe--those with many years of experience,or a hack(me) that messes around on the bench in his spare time.
Brad
Never let your schooling get in the way of your education.