GL,
If your circuit works that way, then consider the attached drawing.
First, I've redrawn your circuit yet again, but this time with emphasis on Q2 (it drives the load). You may notice that the 9V is simply turning Q1 partially (or fully) ON so as to channel VD to Q2's Gate.
In the second part of the drawing, I've attempted to simplify the circuit by eliminating Q1, and providing bias to Q2 through Rbias. It would be interesting to see if that would still work.
I would also be interested to see if the first circuit still works with wire "p" removed. I believe it may be unnecessary. There is a balancing act between the negative Q2 bias applied by the 9V, and a positive bias applied by Q1. It's just a question of whether the negative bias is even required, because we know that Q2 ultimately needs a positive bias to operate.
.99
« Last Edit: 2012-03-09, 03:33:46 by poynt99 »
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