Rosemary: MileHigh - I have been assured that there's always a marginal drop in voltage across a capacitor when it's disconnected from its charge source. Is that what you're relying on? Which makes which of the two us 'morally bankrupt'? The answer is no there is no marginal voltage drop across a capacitor when it's disconnected from a source. You saw the calculations yourself in the previous postings so stop trying to beat around the bush. You are morally bankrupt because you refuse all suggestions for making alternative measurements on your setup. I can only guess that you are afraid of what those measurements may say - that the batteries are discharging energy while the setup runs. That will bring down your "COP infinity" fantasy like a house of cards. You are also morally bankrupt because you turned on Poynt and others when it came to his guidance about how to do serious power measurements. You turned on him like an animal. You praised him while you learned about your circuit from him but the moment it appeared that doing serious measurements were going to ruin your "COP infinity" fantasy you turned on him like an animal. And you need to substantiate your claim that a battery can discharge current through any transistor at all without passing through its source leg. Alternatively IF the discharge is through the source leg of Q2 to the Gate of Q1 - then you also need to argue how it IGNORES the negative charge applied to the Gate of Q1.
Don't repeat your claim. Argue it. Otherwise you have NO credibility with this claim of yours that the battery is discharging through it's Q2's source leg to the gate of Q1. And it really doesn't matter how indignant you pretend to be when you 'claim' that this happens - IT SIMPLY DOES NOT. It CANNOT. Unless it can bypass Q1 which is where the signal probe is sitting. And that applied signal is NEGATIVE. The above is more complete and utter nonsense talk from you and you make attempts to put words in my mouth, things that I never said. That is yet again more moral bankruptcy from you. Forget about the MOSFETs, I am not even talking about them. The test I am proposing is identical to your standard setup with the one exception where we substitute one of your 12.6 volt batteries for a large capacitor charged to 12.6 volts. GO READ THE TEST PROCEDURE AGAIN. There is a clear example showing all of the calculations for determining the output power from the set of batteries while your circuit runs. You apparently cannot stomach the thought that a different test will show that the batteries are actually discharging and pumping power into the load. In other words, there is no "COP infinity" fantasy. No distractions, no deflections, no crap from you Rosemary. The most important thing is the TRUTH. The truth is more important than me, more important than you, and more important than your fantasies. Do you want to try and discover the truth Rosemary? If you do, then DO THE CAPACITOR TEST AND PUNCH IN THE NUMBERS. Stop all of this monkeying around and making a fool of yourself. MileHigh
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