Check please the attached picture!
You see a rectifier,which converting the primary side AC to DC with a full wave rectifier tube, and charging the output smoothing capacitor. Depending on the frequency of the sine wave, and on the capacitor size, it will take a a certain amount of time to fully charge the capacitor. In that certain amount of time,the energy from the primary side, will be transferred to the capacitor (minus the circuit losses),so there will be a pulsating DC current flowing in the flexible wire until the condenser fully charged.
My question is, in this case, if we put a strong external magnetic field near the flexible wire (which will cause movement in the wire if the current is flowing),and switch on the rectifier for that certain amount of time again, until the capacitor is fully charged, should we except more losses in the energy transfer as in the first case, when there was no magnet there? If yes, how could we calculate this additional loss?
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"A designer knows he has achieved perfection not when there is nothing left to add, but when there is nothing left to take away." Antoine de Saint-Exupery
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