Bill Mehess is this the one??

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Author Topic: Bill Mehess is this the one?? (Read 27139 times)

Chet K	Bill Mehess is this the one?? « on: 2011-08-15, 01:44:16 »
Group: Ambassador Hero Member Posts: 4045	Well fellahs I spoke with Bill this evening,He's got it running down in the basement making power with no input ,hooked to nothing ?? Is this it?? http://www.overunity.com/index.php?topic=11303.0 I sure hope so! He says he can build one in 5 minutes now [even sipping Coffee] And will build one on a live link while he's running the Demmo. Chet PS No he doesn't want your money ,your wife or the keys to the city! He wants what we want. To leave this world a better place then he found it....................... PPS I believe his Handle is Captainpecan

muDped	Re: Bill Mehess is this the one?? « Reply #1 on: 2011-08-15, 07:19:19 »
Group: Tinkerer Hero Member Posts: 3055	The output voltage he's indicated is in the hundreds of milliVolts and he's not specified what the current produced may be. What comes to mind is something akin to a thermocouple or a thermo-electric generator. A solar heated home-made thermocouple is capable of producing significant voltage at tens to hundreds of milliAmperes for a small unit. But then again, it may be something entirely different. Guess we'll have to wait and see... --------------------------- For there is nothing hidden that will not be disclosed, and nothing concealed that will not be known or brought out into the open.

giantkiller	Re: Bill Mehess is this the one?? « Reply #2 on: 2011-08-15, 19:47:07 »
Group: Elite Experimentalist Hero Member Posts: 1593 Frequency equals matter...	I tried... http://www.overunity.com/index.php?topic=11303.msg298006#msg298006 Because: #1: A proclamation. #2: We must wait. #3: Everything is safe. #4: A visitor will show up. --------------------------- http://purco.qc.ca/ftp/

muDped	Re: Bill Mehess is this the one?? « Reply #3 on: 2011-08-15, 20:36:09 »
Group: Tinkerer Hero Member Posts: 3055	Sadly, the love of money or the desire to become wealthy is powerful bad medicine... The way this thing is progressing is very strange. --------------------------- For there is nothing hidden that will not be disclosed, and nothing concealed that will not be known or brought out into the open.

EMdevices	Re: Bill Mehess is this the one?? « Reply #4 on: 2011-08-16, 01:56:34 »
Hero Member Posts: 805	I'll send my friend over there to witness it, he lives in Portland. I'm prepared to be shocked, since voltage is very low, it must be a dirty solar panel!

MileHigh	Re: Bill Mehess is this the one?? « Reply #5 on: 2011-08-16, 05:31:36 »
Group: Guest	I'm about half-way through the OU thread right now. Something that costs about $20 in parts that can be purchased from your local hardware store. Claims that it produces voltage and can charge capacitors. However, no indication of how much current it can output at a given voltage, hence no indication of a power output. I don't know how technical "billmehess" is but that's already an issue. We will see......

Peterae	Re: Bill Mehess is this the one?? « Reply #6 on: 2011-08-16, 09:24:59 »
Group: Administrator Hero Member Posts: 3961	MH surely this means the current is unlimited at any voltage and depends on the scale size of the build Quote I am currently generating a stable 850 mv this and amperage can be scaled to any level of output. I think we need to wait this one out, with no details it's impossible to work out if it's feasible. Personally i think he has done this the right way by not giving out advanced information before a public demonstration is held, although he may need to hire a football stadium to house us OU enthusiasts LOL

wattsup	Re: Bill Mehess is this the one?? « Reply #7 on: 2011-08-16, 14:52:35 »
Hero Member Posts: 520	I asked him what the values of the caps he is loading but no answer. Problem is if the loading caps have high enough uF values, they could be loading the 800mv on their own or via a low voltage circuit in a loop with the loading cap and this could wind up being a total waste of time. As for the way he is disclosing this, it is juvenile and chock full of areas where Murphy's Law can just jump in and screw things up. So many things can go wrong until that date but men with plans think always that everything will go "as planned". Since when? On a different angle, this may also be a good thing since if anyone else has a small device that is OU, they may be compelled to disclose it before Bill does and hence, beat him to the punch. Any takers? lol wattsup --------------------------- http://etherimpress.com

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #8 on: 2011-08-16, 16:07:10 »
Group: Professor Hero Member Posts: 3017	Bill certainly has raised our interest. He says he plans to make money by "selling plans". Perhaps OK -- but I for one wish to make sure this is not just a battery of some sort, that is, running off of chemical energy stored in dissimilar metals -- or pulling a small amount of electrostatic energy out of the air... More on this concern: a friend noted to me that Bill gave his email address: Quote "Not to worry all you good people all the necessry safeguards have been met. I will have a location for the demo nailed down in the next few days. I have received a number of request for direct contact- no problem for me Bill Mehess excel60@hotmail.com" -- post at OU, 15 Aug 2011 Then you find at Youtube, searching for "excel60", the following "water battery" -- http://www.youtube.com/watch?v=TdWKfav5s_8 He claims "no degradation" of the metals, which is doubtful -- over time, this is a battery after all, and the energy comes from chemistry. Is this a useful clue to his present claims? Regrettably, I suspect an "air battery" for Bill's current claims ... which even if it works, will have a cost larger than what one can get today with solar cells (About $1.50 per watt).

BEP	Re: Bill Mehess is this the one?? « Reply #9 on: 2011-08-16, 16:11:24 »
Group: Guest	Quote from: wattsup on 2011-08-16, 14:52:35 On a different angle, this may also be a good thing since if anyone else has a small device that is OU, they may be compelled to disclose it before Bill does and hence, beat him to the punch. Any takers? lol Sure I have a set of 1F caps that will explode on their own without a shorting jumper. Give me a month after I remove the jumpers but I wasn't able to determine when they would explode before

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #10 on: 2011-08-16, 16:22:22 »
Group: Professor Hero Member Posts: 3017	Another youtube video by excel60 (Bill Mehess, we surmise) -- http://www.youtube.com/watch?v=TvNCrDTQZNk&feature=mfu_in_order&list=UL "It will just continue hour after hour, day after day, 24/7 - just by replacing water". And -- http://www.youtube.com/watch?v=lvETzw0KkNc&feature=autoplay&list=ULaiA1FQ4iQGw&index=4&playnext=1 Copper cathode and zinc-coated iron anode. "These water batteries do not wear out". Plus a "little bit of lemon juice". "Doesn't wear out" NO, Bill -- the metals will degrade.

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #11 on: 2011-08-16, 19:53:26 »
Group: Professor Hero Member Posts: 3017	Bill replied that -- Yes, he posted vids under excel60 on water batteries, etc. My question at OU: Quote Quote from: JouleSeeker on Today at 06:03:40 PM Ah -- "excel60" in you email (thanks NP for the observation), leads one to do a search on youtube for excel60 ... And we find an intriguing discussion of "water batteries" http://www.youtube.com/watch?v=TdWKfav5s_8 AND http://www.youtube.com/watch?v=TvNCrDTQZNk&feature=mfu_in_order&list=UL Copper cathode and zinc-coated iron anode (galvanized). (These can be purchased at larger hardware stores.) And a few other interesting vids by excel60. Did you do these "excel60" videos, Bill? Thanks. He said "Yes." But then replied further -- Quote I think I see where you may be going with this so let me clarify a bit All batteries require some kind of electrolyte to work , even the so called dry cell battery use an electrolyte in paste form. Batteries have materials that are consumable Lazerlight did some great work with a dry cell which had mgnesium strips interacting with a carbon center no electrolytes but the magnesium was consumable Batteries increase in voltage when connected in series and in current (amperage) when connected in parallel. My device: No electrolyte No Consumables New Information for all of you: The individal modules increase in both amperage AND voltage when connected in parallel There is a strong non moving mechanical component I'm not sure how his reply/results fit with Ohm's law... curious reply, really.

muDped	Re: Bill Mehess is this the one?? « Reply #12 on: 2011-08-16, 19:59:03 »
Group: Tinkerer Hero Member Posts: 3055	Quote from: PhysicsProf on 2011-08-16, 16:22:22 ... NO, Bill -- the metals will degrade. Absolutely correct! When very tiny current is drawn from the cells the result of electrochemical deterioration is not evident at all. Few experimenters realize the amount of electrical power available from even a small piece of zinc, or aluminum, or magnesium. Electroplaters know; but they're a vanishing breed nowadays. --------------------------- For there is nothing hidden that will not be disclosed, and nothing concealed that will not be known or brought out into the open.

MileHigh	Re: Bill Mehess is this the one?? « Reply #13 on: 2011-08-17, 00:12:04 »
Group: Guest	PhysicsProf: Quote Actually, batteries connected in parallel will have the same voltage (assuming batteries of the same voltage) and therefore the SAME CURRENT (across a resistor, for example) by Ohm's Law, I = V/R. Perhaps a minor point, but as a retired professor of physics, having taught EM for many years, I sort of jump in on points like that. Habit, I guess. Sorry but you're incorrect here. The available current will double if you put two batteries in parallel. At these low power levels putting two "batteries" (or whatever they are) in parallel is not really an issue but if you want to consider all of the angles when it comes to playing with batteries or unknown voltage sources, you would be best off to never put them in parallel. Quoting Billmehess: Quote The device absolutly works in the parallel mode. If I take say 4 modules that are putting out 100 mv ( they do not all put out exactly the same amount I am using this to simply) if I put them in series my voltage is around 170mv if I connect them in parallel the voltage is around 380mv. One of the other devices setting next to it has 6 modules and in parallel they put out around 510 mv and in series 185 mv ? Also the current increases as it should. I know this because I can connect the device to a capacitor (I usually use a electrolytic 25 4900 mf for this purpose) and in one hour I can record the voltage in the cap. The voltage is always directly perportional to the number of modules in parallel, which of course is the way it should be. It doesn't look good at all from reading Billmehess on OU today. The Las Vegas odds-makers are upping the odds for the chances of this being real. They now sit at 1 in 1000, and those are odds within the frame of reference of the forums. Don't shoot me, I am just sharing my honest opinion. This isn't real and it's pretty obvious that Bill is not at a technical level where he can demonstrate mastery over the subject matter at hand. If you make the claim then you are going to be subject to scrutiny whether you like it or not. I will now wait for the post-demo fallout, not up to debating anything about this one personally. MileHigh

EMdevices	Re: Bill Mehess is this the one?? « Reply #14 on: 2011-08-17, 00:40:18 »
Hero Member Posts: 805	I wonder if Bill is confused about the meaning of Series and Parallel, or we don't understand the context or geometry of his device. Placing plates in a battery next to each other can be considered "PARALLEL" but the plates can be connected either in series or parallel from a circuit stand point. Maybe he is talking about geometry here not electrical circuits. @MH Quote Sorry but you're incorrect here. The available current will double if you put two batteries in parallel MH, the Profesor is correct and so are you. Try to understand what he is saying before jumping to conclusions. He is talking about the load current which depends on the voltage, that's why he quoted ohms law. And what you say is also correct, because all batteries have a source impedance and putting two in parallel lowers the source impedance to half, so we can draw twice as much current for the same battery voltage drop (under load), and of course the obvious, putting two batteries in parallel doubles the amphour rating. EM « Last Edit: 2011-08-17, 01:14:56 by EMdevices »

BEP	Re: Bill Mehess is this the one?? « Reply #15 on: 2011-08-17, 02:14:49 »
Group: Guest	I doubt he is confused but I think almost everyone else is. Intentional? Maybe this is a stretch for some... What has the result of twice the potential and twice the stored energy when side by side? "The individal modules increase in both amperage AND voltage when connected in parallel There is a strong non moving mechanical component" When you use two magnets instead of one during induction you double the potential and the energy produced. So this tells me he is using EM induction without obvious relative motion between the magnet and the coil. You can mount a magnet with springs inside a coil and produce several hundred millivolts with nothing more than ambient energy (vibration, sound, etc.). Certainly, this is not new. >>Edit... Maybe I'm off base on this one. I just remembered placing two magnets in parallel with each other yields 4 times the magnetic force not double. Oh well, at least it still increases the amount of induction for relative motion « Last Edit: 2011-08-17, 03:00:37 by WaveWatcher »

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #16 on: 2011-08-17, 05:38:06 »
Group: Professor Hero Member Posts: 3017	Thanks, EMDevices -- I agree (above).. Update from the OU thread: What strikes me is that I calculated the output power from Bill's data, and the result was a mere 53 MICROwatts for TEN modules -- And no one blinked. Not even here. Even if the effect is real -- some kind of electrostatic antenna for example -- the power is TINY. Or am I wrong about this?

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #17 on: 2011-08-17, 06:09:29 »
Group: Professor Hero Member Posts: 3017	I just posted this at OU; again, comments welcomed. Quote OK -- I've checked my math and found it correct, to recap: 53 MICROwatts for Bill's 10-module system (connecting the 6-modules with the 4-modules). See below along with previous posts -- I have also checked from Bill's comments that the 280mV rise in the 4900 uF cap took one hour for "the two sets of modules together in series". But please correct me if my calculations are wrong, because, Bill and other friends, this is a very VERY tiny effect: 1. 53 uW for 10 modules means about 5.3 microwatts/module (average) 2. To reach just ONE watt would thus require about 189,000 modules. 3. Earlier there was an indication that one could get the materials needed to build a module at a hardware store for less than $20. OK, let's say just $10. 4. Combining 2 and 3, we find that for ONE stinkin' watt it will cost roughly $1,890,000 -- nearly 2 million bucks ! 5. Let's take roughly 1 kW to run a house (a low estimate I believe) -- the cost for the modules (with present data) would be $1,890,000,000 or nearly $2 Billion bucks. That's billion with a "B". I can't afford it. 5. By comparison, solar panels are now available for about $1.50 per watt output, a factor of roughly a million CHEAPER than this device, at present. Please correct me if I'm wrong. I hope I'm wrong. OR -- I hope the device can be SCALED up in output POWER by a factor of roughly a million without raising the price... Is this possible? Quote from: billmehess on August 16, 2011, 10:34:53 PM Yes this would certainly help me , and yes I meant to say uf not mf. When I connect the two sets of modules together in series I get again around a 700 mv out put , but the total of the summation of all the individuals is around 1400 mv, voltage loss? Anyway at 700 mv connected to the cap. and using a multimeter and starting with the cap reading 0.00 the cap will charge at the rate of about 180 mv/hour. Now I have a way to increase the current output substanially to radically improve the amperage available. Based on these figures could you calculate the power output. The physical size of the 10 modules is around 12" x 5" x 5" total for all 10. This can be scaled down greatly but that size is not really of concern to me at this point in the game. Bill I just re-read above the voltage on the cap after 1 hr is 280 mv not 180 mv.

MileHigh	Re: Bill Mehess is this the one?? « Reply #18 on: 2011-08-17, 11:01:00 »
Group: Guest	PhysicsProf: Assuming that we are talking about some sort of voltage source with a high-impedance output, then using the cap charging method would not be my preferred way to calculate the power output. The way you crunched the numbers was oversimplified because you did not attempt to derive the output impedance of the device using the provided data. Also, Billmehess' statement that the cap could be charged at "280 millivolts per hour" would seem to indicate that he is not familiar with the exponential waveform associated with capacitor charging and the RC time constant. All that Billmehess has to do is connect something like a 1-megaohm potentiometer to his array and adjust the resistance until the voltage output drops by half, and then measure that resistance value with a mulimeter. That will give you the impedance match and therefore tell you the output impedance of his device and at the same time tell you the maximum possible output power from the device. This is all based on the preliminary and presumably reasonable assumption that this device as a source of electrical power more or less resembles a high-impedance voltage source. Unfortunately Billmehess is being led through this exercise as opposed to leading. If he is making the OU proposition and talking about registering patents one would expect that he or one of his associates with more technical knowledge would at least be able to characterize the device and be able to tell you it's power output capabilities before making the preliminary announcement. The fact that it is 12" x 5" x 5" and only (allegedly) generates power on the order of microwatts is also a major issue. It could very well be an effect related to what WaveWatcher stated. You have a physically large device sitting in a bath of ambient thermal energy and it's producing microwatts of power. Not only would it be overwhelmingly expensive to get usable power from but it would also be overwhelmingly huge. Billmehess has made claims of delivering "considerably more output" after he incorporates some upgrades. We will have to see if he can deliver on that. The bottom line is that even if the power output is low, it would still be an Earth-shattering event if it was indeed true. However, for me personally, this is all simply not adding up and there is a conventional explanation for all of this and my money is on WaveWatcher. MileHigh

NickZ	Re: Bill Mehess is this the one?? « Reply #19 on: 2011-08-17, 16:37:37 »
Group: Guest	Guys: I really don't get what this is all about. There is practically no output from what Bill is saying, so... Seams like another game to me, as always. Hopefully there is more to this. But, will it even light an led???

wattsup	Re: Bill Mehess is this the one?? « Reply #20 on: 2011-08-17, 17:09:16 »
Hero Member Posts: 520	This morning before leaving for the office, I took a 4000 uF 25vdc capacitor and put my volt meter on it and it showed a steady 0.387 vdc, sometimes hitting the 0.388 then back. But it stayed there using nothing. I tried moving a magnet near the capacitors metallic casing and there is no effect. So, is that OU? Now if you put a very small circuit on that capacitor that can click on and off a small transistor to cause some pulsing in anyway through a parallel coil, would that increase the capacitors loading, don't know, but the capacitor itself seems to be doing a good job on its own. wattsup --------------------------- http://etherimpress.com

PhysicsProf	Re: Bill Mehess is this the one?? « Reply #21 on: 2011-08-17, 20:22:07 »
Group: Professor Hero Member Posts: 3017	Quote from: MileHigh on 2011-08-17, 11:01:00 All that Billmehess has to do is connect something like a 1-megaohm potentiometer to his array and adjust the resistance until the voltage output drops by half, and then measure that resistance value with a mulimeter. That will give you the impedance match and therefore tell you the output impedance of his device and at the same time tell you the maximum possible output power from the device. [snip] MileHigh MH -- would you spell that out, pls -- say the voltage drops by half with a resistance on the pot of 100Kohms -- what is "the maximum possible output power from the device"?

MileHigh	Re: Bill Mehess is this the one?? « Reply #22 on: 2011-08-17, 23:00:58 »
Group: Guest	Here is a good link: http://www.qsl.net/wa5bxo/power.html The power out is the "half" voltage squared divided by the resistance value. Therefore the lower the output impedance of the source the higher the maximum power flow is. MileHigh

EMdevices	Re: Bill Mehess is this the one?? « Reply #23 on: 2011-08-18, 00:44:45 »
Hero Member Posts: 805	Professor, I simulated this graph for you so you can see the maximum power delivery condition. See chart. When the battery source impedance (Rs) = load impedance (Rl), we have a condition of maximum power delivery to the load. For reactive circuits or general impeances, the load has to be equal to the conjugate of the source impedance. Note: This condition does not mean the battery's internal voltage source is delivering the maximum power it can. Obviously not. The maximum is when you short the terminals of the battery and then all that you have in the circuit is the internal voltage source in series with the internal battery source impedance. This produces the largest current possible. The battery will dissipate this power as heat generated in the internal source impedance or resistance. EM ------------------------ Bill Mehess is this the one?? loadimp.JPG (50.35 kB, 957x761 - viewed 1001 times.)

BEP	Re: Bill Mehess is this the one?? « Reply #24 on: 2011-08-18, 02:48:54 »
Group: Guest	I must caution those few capable of determining the internal resistance of their batteries and other energy sources. In the battery world it is safe to assume that applying a load impedance matching that of the source battery will probably end up as a disaster. Impedance matching is not always the best thing to do between source and load. Keep in mind that when your load and battery have matched impedance 1/2 of the energy used is wasted by the battery as heat. It can be better to have a higher impedance in the load. You want as much of the expended energy as possible doing useful work not boiling out your battery.

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