@ION
he device looks to be about 2x2 by 1/2 inch or 2 cubic inches of volume. There are 1728 cubic inches per cubic foot so we could pack 864 of these per cubic foot. This would mean we have 43.2 watts-Hrs per cubic foot radiated power density if it were real.
It doesn't work like that, we can not pack the receivers too close to each other because they interfere and detune. I showed this in my wireless power videos from a few years ago.
This "invention" or project is nothing new. There's been a product out there for a while, and probably not just one.
I'm actually working on a concept to coherently tune a few receivers in close proximity, to the same frequency! As I move individual modular receivers closer to an aggregate of receivers, like tiles in a grid, I can scale my antenna aperture, without detuning every module. It's adaptable!
EM
PS, that students energy harvester probably has a tuned coil for the low frequency fields and he is just coupling magnetically and in close proximity to them. For the wifi and cellular phone frequencies, he uses an antenna.
PS. Ok, it's time for an antenna and radiated fields discussion again!
The time average power flow density flowing through space or anywhere, is given by 1/2 Re(ExH), where E and H are the electric and magnetic field vectors, respectively. The ratio of they magnitude, E/H = 377 ohms in free space. That is, free space has a characteristic impedance of 377 ohms.
Now, an antenna has an effective aperture, which is not necessarily the same as its size and its determined by how well it is tuned. For example, a tuned coil can have an effective aperture 1000's of times larger then its physical size.
To determine how much power can be received, multiply the effective aperture area of the antenna times the average power density of the electromagnetic fields. That's it, very easy and straight forward! (except figuring out your antennas effective aperture LOL)
EM
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Topic: What do you consider to be OU. (Read 53907 times)
